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For a triangle, the formula for the area is: A = (BH)/2

7*5/2 = 35/2 = 17.5

17.5 m

(If anyone else knows what a "sub" of a triangle is, please edit!)

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What is the area of an equilateral triangle inscribed in a circle of radius 4cm?

Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.


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Half of a triangle is typically referred to as a "triangle" as well, since dividing it does not create a different geometric shape but simply results in two smaller triangles. However, in the context of specific divisions, such as when a triangle is split by a median, each resulting triangle can be described as a "sub-triangle." If a triangle is divided by its altitude, the halves can be called "right triangles," depending on the original triangle's dimensions.


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Related Questions

Write a vb program to calculate the area of an triangle?

Sure thing, honey. Here's a VB program to calculate the area of a triangle: Module CalculateTriangleArea Sub Main() Dim base As Double = 5 Dim height As Double = 10 Dim area As Double = 0.5 * base * height Console.WriteLine("The area of the triangle is: " & area) End Sub End Module Just copy and paste this bad boy into your VB editor, adjust the base and height values as needed, and you'll have your triangle area faster than you can say "Betty White is a national treasure".


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What is the area of an equilateral triangle inscribed in a circle of radius 4cm?

Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.


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Did anyone try to sail in a small boat through the Bermuda triangle?

The Triangle is a manufactured mystery. Given the weather, type and amount of vessels in the area, no one has shown that an abnormal number of vessels have been lost. A lot of the vanishings either never happened, didn't happen in the Triangle, or are for known reasons (terrible storms, etc.). So there is no reason why a sub would avoid the area.