-3 + 4 + (-2) = 1 + (-2) = 1 - 2 = -1.
A sum of 4 is more likely. Out of the 36 possible outcomes with a pair of 6-sided dice, only one will have a sum of 2 {1-1}. Three of the possibilities sum to 4. {1-3, 2-2, 3-1}
10, unless they are non collinear vectors.
The question is ambiguous.Does it want the sum of the squares, or the square of the sum ? They're different.Here are both:1). Sum of the squares: . (1)2 + (2)2 + (3)2 + (4)2 + (5)2 = 1 + 4 + 9 + 16 + 25 = 552). Square of the sum: . (1 + 2 + 3 + 4 + 5 )2 = (15)2 = 225
Sum = -5 - 3 - 2 + 14 = 4 Count = 4 So mean = Sum/Count = 4/4 = 1
-3 + 4 + (-2) = 1 + (-2) = 1 - 2 = -1.
-2
3
A sum of 4 is more likely. Out of the 36 possible outcomes with a pair of 6-sided dice, only one will have a sum of 2 {1-1}. Three of the possibilities sum to 4. {1-3, 2-2, 3-1}
10, unless they are non collinear vectors.
If the question is - the sum of 1/6, 2/3 and 1/4 then the answer is; 13/12, or 1 1/12.
The question is ambiguous.Does it want the sum of the squares, or the square of the sum ? They're different.Here are both:1). Sum of the squares: . (1)2 + (2)2 + (3)2 + (4)2 + (5)2 = 1 + 4 + 9 + 16 + 25 = 552). Square of the sum: . (1 + 2 + 3 + 4 + 5 )2 = (15)2 = 225
2/3 + 1/4 = 8/12 + 3/12 = 11/12
It is 1 - Pr(rolling a sum of 5 with two dice) = 1 - Pr(1+4 or 2+3 or 3+2 or 4+1) = 1 - 4/36 = 8/9
4
Sum = -5 - 3 - 2 + 14 = 4 Count = 4 So mean = Sum/Count = 4/4 = 1
Any two mixed numbers such that their whole number is 1 and the sum of the fractional parts is 1, eg: 1 1/4 + 1 3/4 1 1/3 + 1 2/3 1 3/7 + 1 4/7