To find the sum of two thirds, you simply add the two fractions together. So, 2/3 + 2/3 = 4/3. To simplify the sum, you can convert the improper fraction 4/3 to a mixed number, which is 1 1/3. Therefore, the sum of two thirds is 1 1/3.
Any two mixed numbers such that their whole number is 1 and the sum of the fractional parts is 1, eg: 1 1/4 + 1 3/4 1 1/3 + 1 2/3 1 3/7 + 1 4/7
13 1+3=4 1-3=-2
For a sum = 12, there's only one (6 + 6), 1/36 For a sum = 4, there's three: 2/36 (1 + 3) + 1/36 (2 + 2) = 3/36
since rolling a dice can give you 36 possible combinations, there are 1/9 chances that you will get a sum of 5. 1+4 2+3 3+2 4+1 the 4 equations above will produce a sum of 5 so,the probability is 4/36, or 1/9.
-3 + 4 + (-2) = 1 + (-2) = 1 - 2 = -1.
-2
A sum of 4 is more likely. Out of the 36 possible outcomes with a pair of 6-sided dice, only one will have a sum of 2 {1-1}. Three of the possibilities sum to 4. {1-3, 2-2, 3-1}
3
10, unless they are non collinear vectors.
If the question is - the sum of 1/6, 2/3 and 1/4 then the answer is; 13/12, or 1 1/12.
The question is ambiguous.Does it want the sum of the squares, or the square of the sum ? They're different.Here are both:1). Sum of the squares: . (1)2 + (2)2 + (3)2 + (4)2 + (5)2 = 1 + 4 + 9 + 16 + 25 = 552). Square of the sum: . (1 + 2 + 3 + 4 + 5 )2 = (15)2 = 225
It is 1 - Pr(rolling a sum of 5 with two dice) = 1 - Pr(1+4 or 2+3 or 3+2 or 4+1) = 1 - 4/36 = 8/9
4
Sum = -5 - 3 - 2 + 14 = 4 Count = 4 So mean = Sum/Count = 4/4 = 1
Any two mixed numbers such that their whole number is 1 and the sum of the fractional parts is 1, eg: 1 1/4 + 1 3/4 1 1/3 + 1 2/3 1 3/7 + 1 4/7
Two factors of what? To sum to -2, some possibilities are: -1, -1 => what is 1 0, -2 => what is 0 1, -3 => what is -3 2, -4 => what is -8 3, -5 => what is -15 4, -6 => what is -24