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When the sum of a number pluse 3 is squated it is 11 more than the sum of the number plus 2 when squared?
Call the unknown number n. From the problem statement (n + 3)2 - (n + 2)2 = 11. Expanding both squares yields n2 + 6 n + 9 - (n2 + 4n + 4) = 11, or 2 n + 5 = 11, 2n = 6, n = 3.
What is the sum of the interior angle measure is 1620?
The sum of the interior angle measures of a polygon can be calculated using the formula ( S = (n - 2) \times 180 ), where ( n ) is the number of sides. To find the number of sides for which the sum of the interior angles is 1620 degrees, we can set up the equation: ( (n - 2) \times 180 = 1620 ). Solving for ( n ), we get ( n - 2 = 9 ), so ( n = 11 ). Therefore, a polygon with a sum of interior angles measuring 1620 degrees has 11 sides, making it an 11-sided polygon, or hendecagon.
The sum of a number and 6?
n = number n + 6 ======
C program to find sum of 'n' number using function?
void main () { int no1, sum, n; clrscr() sum = 0; n = 1; printf("\n enter the number to which sum is to be generated"); scanf("%d",&no1); while(n<=no1) { sum=sum+n; n=n+1 } printf("\n the sum of %d = %d, no1, sum"); getch (); }
Write a java program to find out the sum of a number of n digits?
class Sum_Of_Digits { public static void printSumandnoofdigits(int n) { int temp = n; int count = 0; int sum = 0; while ( n > 0 ) { sum = sum + n % 10; n = n / 10; count ++; } System.out.println("The number is..." + temp ); System.out.println("The sum of digits is..." + sum); System.out.println("The number of digits is..." + count); } }
The sum of a number and 11?
The sum of a number and 11 can be represented as x + 11, where x is the unknown number. This expression denotes adding 11 to the unknown number. If you know the value of x, you can simply add 11 to find the sum. If x is unknown, the expression x + 11 remains as an algebraic representation of the sum.
What is the sum of the cube of a number and eleven times the number?
n3 + 11*n
When the sum of a number pluse 3 is squated it is 11 more than the sum of the number plus 2 when squared?
Call the unknown number n. From the problem statement (n + 3)2 - (n + 2)2 = 11. Expanding both squares yields n2 + 6 n + 9 - (n2 + 4n + 4) = 11, or 2 n + 5 = 11, 2n = 6, n = 3.
If the sum of the interior angles of a polygon is 1620 how many sides does the polygon have?
11 (interior angles total 18 x 90)
The sum of a number and 2?
let the number be n, then the sum of the number and 2 is n+2
What is the sum of the even numbers between 1and 11?
write an algo to find the sum of even number from 1to n
A sum of a number and twice its number?
If the number is n, then twice the number is 2n and the sum of the two is n + 2n = 3n.
What is the sum of the interior angle measure is 1620?
The sum of the interior angle measures of a polygon can be calculated using the formula ( S = (n - 2) \times 180 ), where ( n ) is the number of sides. To find the number of sides for which the sum of the interior angles is 1620 degrees, we can set up the equation: ( (n - 2) \times 180 = 1620 ). Solving for ( n ), we get ( n - 2 = 9 ), so ( n = 11 ). Therefore, a polygon with a sum of interior angles measuring 1620 degrees has 11 sides, making it an 11-sided polygon, or hendecagon.
Find the sum of the angle measures in a 11-gon?
1620 the equation to find the sum of the interior angles for any regular polygon is: (n-2)x180, where n=the number of sides.
The sum of a number and 6?
n = number n + 6 ======
The sum of a number and 8?
This is simple algebra. Let the unknown number be n. Then the sum of this number and 8 = n + 8.
C program to find sum of 'n' number using function?
void main () { int no1, sum, n; clrscr() sum = 0; n = 1; printf("\n enter the number to which sum is to be generated"); scanf("%d",&no1); while(n<=no1) { sum=sum+n; n=n+1 } printf("\n the sum of %d = %d, no1, sum"); getch (); }
