34
38-4=34
15, because 15+19=34 (and 19-15=4)
34 + 2 = 36whew !
21 and 13.. 21-13=8 21+13=34 34/2 = 17,+4 = 21... 34-21 = 13
-- Their sum is (36 + 34) = 70, not 72. -- Their difference is (36 - 34) = 2, not 4. -- Other than that, 36 and 34 are a terrific answer ! But 38 and 34 would be better.
2*4 + 3*x = 34
x^2
The smaller number is x. The larger number is 4x + 4. Their sum is 34. Therefore x + 4x + 4 = 34. 5x + 4 = 34. 5x = 30. x = 6. The smaller number is 6. The larger number is (4 x 6) + 4 = 28.
34
38-4=34
34.
1 + 2 + 4 + 17 + 34 + 68 = 126
15, because 15+19=34 (and 19-15=4)
34 (the sum) divided by 2 (people) = 17 Now, account for the "4" difference, while maintaining the sum of 34. In other words, add "1" to one age, while subtracting "1" from the other until the difference is "4". 19 + 15 = 34 19 - 15 = 4 However, the question is asking for the product of the ages. 19 x 15 = 285. 285
There are 59 possible sets of 4 factors and I am certainly not prepared to list them all.2, 3, 4, 12 has the smallest sum (21) in the required range.4, 5, 10, 15 has the largest sum (34) in the required range.There are 59 possible sets of 4 factors and I am certainly not prepared to list them all.2, 3, 4, 12 has the smallest sum (21) in the required range.4, 5, 10, 15 has the largest sum (34) in the required range.There are 59 possible sets of 4 factors and I am certainly not prepared to list them all.2, 3, 4, 12 has the smallest sum (21) in the required range.4, 5, 10, 15 has the largest sum (34) in the required range.There are 59 possible sets of 4 factors and I am certainly not prepared to list them all.2, 3, 4, 12 has the smallest sum (21) in the required range.4, 5, 10, 15 has the largest sum (34) in the required range.
It is: 512+34 = 546