The question seems to be asking for two operations: the sum of 38 and the product of 63 with some other number. However, since no specific number is given to multiply with 63, it’s unclear what the product refers to. If you simply want the sum of 38 and 63, that would be 101. Please clarify if you meant something different!
The sum of 36 plus 63 can be expressed as a product by first calculating the sum, which is 99. This can be factored and expressed as a product of its prime factors: (99 = 9 \times 11), or as (3^2 \times 11). Thus, the expression for the sum of 36 and 63 as a product is (9 \times 11).
7(7 + 9)
The sum of 54 and 63 is 117. This can be expressed as the product of 9 and 13, where 9 and 13 are relatively prime addends. Therefore, 54 + 63 = 9 × 13.
They are: 78 and 63
"x" is the symbol for product or multiple: not sum. Consequently the question is unclear.
The sum of 36 plus 63 can be expressed as a product by first calculating the sum, which is 99. This can be factored and expressed as a product of its prime factors: (99 = 9 \times 11), or as (3^2 \times 11). Thus, the expression for the sum of 36 and 63 as a product is (9 \times 11).
3 (21+5)
'Product' is another way of saying 'multiply the two numbers together'.
7(7 + 9)
The sum of 54 and 63 is 117. This can be expressed as the product of 9 and 13, where 9 and 13 are relatively prime addends. Therefore, 54 + 63 = 9 × 13.
The questioner needs to make up his/her mind whether the question is about the sum or product.
445
They are: 78 and 63
"x" is the symbol for product or multiple: not sum. Consequently the question is unclear.
To find two numbers whose sum is 16 and product is 63, we can set up the equations ( x + y = 16 ) and ( xy = 63 ). By substituting ( y = 16 - x ) into the product equation, we get ( x(16 - x) = 63 ), which simplifies to ( x^2 - 16x + 63 = 0 ). Solving this quadratic equation, we find the numbers are 7 and 9, as ( 7 + 9 = 16 ) and ( 7 \times 9 = 63 ).
7+9=16 7x9=63 63-16 = 47
7 & 9 7 + 9 = 16 7 X 9 = 63