2!!
The sum of a number plus 3 to the square root of 9 to the sum of 2 would equal -2. This is a math problem.
9. Because 3 times 3 equals 9
9 and 3 because 9+3 =12 and 9/3 = 3
1+2+3+9+999+10000 = 11014
It is 9*(2 + 3)
2!!
Because 9*3 = 27 and 2+7 = 9
The sum of the digits will be divisible by 3 if the number itself is divisible by 3. Examples: 3999 -> 3 + 9 + 9 + 9 = 30 126 -> 1 + 2 + 6 = 9 6012 -> 6 + 1 + 2 = 9
9(2 + 3)
9. Because 3 times 3 equals 9
9 and 3 because 9+3 =12 and 9/3 = 3
(2 x 9) + (3 x 9) = 5 x 9 = 45
9(2 + 3)
It is: 2/15 plus 3/9 = 7/15
1+2+3+9+999+10000 = 11014
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)