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That is simple! Knowing that there are only 8 numbers BETWEEN 1 and 10, half of them even and half odd, you would have the solution:

x+(x+2)+(x+4)+(x+6)=?;x=2 <--- See here i have 4 quantities since half of 8 is 4.

Then if we remove the parentheses, we would have:

=x+x+2+x+4+x+6

Then combine similar terms:

=4x+12

Then substitue the value of x:

=4(2)+12

=8+12

=20

:)

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Q: What is the sum of all even numbers between 1 and 10?
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