0
That is simple! Knowing that there are only 8 numbers BETWEEN 1 and 10, half of them even and half odd, you would have the solution:
x+(x+2)+(x+4)+(x+6)=?;x=2 <--- See here i have 4 quantities since half of 8 is 4.
Then if we remove the parentheses, we would have:
=x+x+2+x+4+x+6
Then combine similar terms:
=4x+12
Then substitue the value of x:
=4(2)+12
=8+12
=20
:)
Still curious? Ask our experts.
Chat with our AI personalities
Steve
Beau
TaigaAdd your answer:
Earn +20 pts
What is the sum of all even numbers between 0 and 398?
The sum of all even numbers between 0 and 398 (2-396) is 157,212. If you include 398 the sum is 158,802.
What is the difference between the sum of all even numbers and the sum of all odd numbers from 0 through 1000?
500
What is the sum of all even numbers between 10 and 20?
To find the sum of all even numbers between 10 and 20, we first need to identify the even numbers in that range. The even numbers between 10 and 20 are 10, 12, 14, 16, and 18. Adding these numbers together, we get 10 + 12 + 14 + 16 + 18 = 70. Therefore, the sum of all even numbers between 10 and 20 is 70.
What is the sum of all even numbers 10 and 20?
The sum of all even numbers between 10 and 20 can be found by adding the even numbers in that range. The even numbers between 10 and 20 are 12, 14, 16, and 18. Adding these numbers together, 12 + 14 + 16 + 18 equals 60. Therefore, the sum of all even numbers between 10 and 20 is 60.
What will be the sum of first 25 even numbers?
There are 12 even numbers between 2 and 24 inclusive.The sum is 154.
