4 + y.
16 + x = y
There is no two digit number which, when added to Y gives Y.
x + y = 22 x - y = 12 x = 17 y = 5
12 Let x represent the smaller number and y the larger number. From the problem, we have two equations: x+y=3(y-x) y=x+6 Now solve for x: x+(x+6)=3((x+6)-x) 2x+6=18 x=12 Now use this to solve for y: y=x+6=6+6=12
4 + y.
3x-y=8 x+y=12 3x(12-x)=8 3x-12+x=8 4x-12=8 4x=20 x=5 x+y=12 5+y=12 y=7
Let the tens digit be x, and ones digit be y. So we have: x + y = 12 x = y + 2 Substitute y + 2 for x to the first equation: x + y = 12 (y + 2) + y = 12 y + y + 2 - 2 = 12 - 2 2y = 10 2y/2 = 10/2 y = 5 the ones digit y + 2 = 5 + 2 = 7 the tens digit Thus, the number is 75.
16 + x = y
There is no two digit number which, when added to Y gives Y.
1/x+1/y y/xy+x/xy x+y/xy=12/24 12/24=1/2 1/2 is the answer.
x+y=20 x-y=4 2x=24 x=12 y=8
x=3y-5 x+y=43 3y-5+y=43 2nd Number: 12 1st Number: 31
You have to find out what the unknown number is. Example: x= 2y-4 y=12 What this is saying is you have to find out what x is if y is 12. So the sum reads 2x12-4. X=20
x+y=6x^2 + y^2=20 x=2 and y=4 or vice versa
x + y = 22 x - y = 12 x = 17 y = 5
y=x+70