4 + y.
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The equation: 4 - (6 + X) = Y For every different number X there is a different Y.
Y = 4 (x+8)
In an addition sum, if the missing number is the first number, for example, x + 5 = 10, then to find x, perform the sum 10 - 5, producing the solution x = 5. In a subtraction sum, if the missing number is the second number, for example, 7 - y = 4, then to find y, perform the sum 7 - 4 = 3, production the solution y = 3.
I believe that it is something like (4+x) or maybe 4+x=y
5+y=12