The equation: 4 - (6 + X) = Y For every different number X there is a different Y.
Y = 4 (x+8)
In an addition sum, if the missing number is the first number, for example, x + 5 = 10, then to find x, perform the sum 10 - 5, producing the solution x = 5. In a subtraction sum, if the missing number is the second number, for example, 7 - y = 4, then to find y, perform the sum 7 - 4 = 3, production the solution y = 3.
I believe that it is something like (4+x) or maybe 4+x=y
5+y=12
The equation: 4 - (6 + X) = Y For every different number X there is a different Y.
x+y=6x^2 + y^2=20 x=2 and y=4 or vice versa
Y = 4 (x+8)
In an addition sum, if the missing number is the first number, for example, x + 5 = 10, then to find x, perform the sum 10 - 5, producing the solution x = 5. In a subtraction sum, if the missing number is the second number, for example, 7 - y = 4, then to find y, perform the sum 7 - 4 = 3, production the solution y = 3.
Call your number 10x + y. x = y + 2 and 10x + y = 4 + 6(x + y) Substitute y + 2 for x: 10(y + 2) + y = 4 + 6((y + 2) + y) This simplifies to 10y + 20 + y = 4 + 6y + 12 + 6y, ie 20 - 16 = 12y - 11y so y = 4 and x = 6 Your number is 64, which is indeed 4 more than the sum of its digits.
I believe that it is something like (4+x) or maybe 4+x=y
Algebraic expressions are useful for translating problems into the language of mathematics. An algebraic expression for the problem "6 times the sum of 4 and y" would be: 6(4+y) = 24 + 6y.
x+y=20 x-y=4 2x=24 x=12 y=8
6(4+y)
4(y+1)
5+y=12
16 + x = y