Well, honey, if you add up the digits 1-6 inclusive by 3, you're looking at 3 + 6 + 9 + 12 + 15 + 18, which gives you a grand total of 63. So, grab a calculator if you need to, but that's the sum you're gonna get.
The factors of 3 are 1 and 3. The sum of the digits of these factors is calculated as follows: for 1, the sum of its digits is 1, and for 3, the sum of its digits is 3. Therefore, the total sum of the digits of the factors of 3 is 1 + 3 = 4.
The digits of 330 are 3, 3 and 0, so the sum of those digits means add them up - 3+3+0=6
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
There are no 3-digit whole numbers whose digits sum to 3. The smallest 3-digit number is 100, and the largest is 999, but in neither case is the sum of the digits equal to 3.
The factors of 3 are 1 and 3. The sum of the digits of these factors is calculated as follows: for 1, the sum of its digits is 1, and for 3, the sum of its digits is 3. Therefore, the total sum of the digits of the factors of 3 is 1 + 3 = 4.
How many permutations of 3 different digits are there, chosen from the ten digits 0 to 9 inclusive?
The digits of 330 are 3, 3 and 0, so the sum of those digits means add them up - 3+3+0=6
A number is divisible by 3 if the sum of its digits is divisible by 3.
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)
The sum of the digits is a multiple of 3
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
There are no 3-digit whole numbers whose digits sum to 3. The smallest 3-digit number is 100, and the largest is 999, but in neither case is the sum of the digits equal to 3.
A number is divisible by 3 if the sum of its digits is a multiple of 3. A number is divisible by 6 if the sum of its digits is a multiple of 3 and it's even. A number is divisible by 9 if the sum of its digits is a multiple of 9.
All multiples of 3 have digits that add up to a multiple of 3. There are 333 multiples of 3 between 1 and 1000.
If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.
A dozen is equal to 12. The sum of the digits of 12 are 1 + 2 = 3.