Well, honey, if you add up the digits 1-6 inclusive by 3, you're looking at 3 + 6 + 9 + 12 + 15 + 18, which gives you a grand total of 63. So, grab a calculator if you need to, but that's the sum you're gonna get.
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To find the sum of the digits 1-6 inclusive by 3, we first need to identify the numbers that are divisible by 3 in this range. These numbers are 3 and 6. The sum of these two numbers is 3 + 6 = 9. Therefore, the sum of the digits 1-6 inclusive by 3 is 9.
Oh, dude, so like, you got 1, 2, 3, 4, 5, 6, right? And you wanna add them up by 3? Okay, let's do some basic math here. 1 + 2 + 3 + 4 + 5 + 6 equals 21. So, like, that's your answer, man.
The digits of 330 are 3, 3 and 0, so the sum of those digits means add them up - 3+3+0=6
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
There are no 3-digit whole numbers whose digits sum to 3. The smallest 3-digit number is 100, and the largest is 999, but in neither case is the sum of the digits equal to 3.
A number is divisible by 3 if the sum of its digits is a multiple of 3. A number is divisible by 6 if the sum of its digits is a multiple of 3 and it's even. A number is divisible by 9 if the sum of its digits is a multiple of 9.