Q: What is the sum of the first two multyples of 8?

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The sum of the first 8 odd numbers is 64.

You add two addends to get a sum. For example, in 3 + 5 = 8, 3 and 5 are addends, and 8 is the sum.

5 and 3.they have the sum of 8: 5+3=8and the difference of two: 5-3=2Hope this helps :-)

The expression that represents two times the sum of p and 8 is 2(p + 8).

6 and 2 are a number pair with a sum of 8 and a product of 12

Related questions

The sum of the first 8 odd numbers is 64.

The sum of the first 8 prime numbers is 77.

Sum of the first 15 positive integers is 15*(15+1)/2 = 120 Sum of the first 15 multiples of 8 is 8*120 = 960

The difference of two numbers is 8. Their sum is 22. What are the two numbers?

57

Two Numbers are 8 and 6. This is how. 8 + 6 = 14 and 8*8 + 6*6 = 64 + 36 = 100

the sum is the two numbers that you are adding. 8+10=18

The probability of rolling a sum of 8 on one roll of a pair of dice is 5/36.The probability of not rolling a sum of 8 on one roll of a pair of dice is 31/36.The probability of rolling a sum of 8 twice on two rolls of a pair of dice is(5/36)(5/36) = (5/36)2 .The probability of rolling first a sum of 8 and then rolling a sum that is not 8 on thesecond roll is (5/36)(31/36).The probability of rolling a sum that is not 8 on the first roll and rolling a sum of 8in the second roll is (31/36)(5/36).So The probability of rolling a sum of 8 at least one of two rolls of a pair of dice is(5/36)2 + (5/36)(31/38) + (31/36)(5/36) = 0.258487654... ≈ 25.8%.

Suppose the first number is x Then the second is 3x - 8 Their sum is x + 3x - 8 = 4x - 8 = 56 So 4x = 64 and so x = 16 Then the second number is 3x - 8 = 40 The numbers are 16 and 40.

You add two addends to get a sum. For example, in 3 + 5 = 8, 3 and 5 are addends, and 8 is the sum.

8 + 3 = 11 8 x 3 = 24 The two numbers are therefore 8 and 3.

5 and 3.they have the sum of 8: 5+3=8and the difference of two: 5-3=2Hope this helps :-)