Sum of the first 15 positive integers is 15*(15+1)/2 = 120 Sum of the first 15 multiples of 8 is 8*120 = 960
5 + 10+15+20=50 ans
Sum of first 25 multiples of 44+8+12....100taking 4 common4(1+2+3+4....+25) = 4*325 =1300
Well, the multiples of 8 go "8, 16, 24...etc." The first four multiples of 8 over 20 are 24, 32, 40, and 48. i) 24 + 32 = 56 ii) 56 + 40 = 96 iii) 96 + 48 = 144 Therefore the sum is 144.
8A + (8A+8) + (8A+16) = 888 24A + 24 = 888 ===> 24A = 864 ===> A = 36 The multiples are 8A, 8A+8, 8A+16 = 288, 296, 304. Sum = 888.
Sum of the first 15 positive integers is 15*(15+1)/2 = 120 Sum of the first 15 multiples of 8 is 8*120 = 960
It is: 8+16+24+32 = 80
5 + 10+15+20=50 ans
The first two multiples are 9 and 8.
4 + 8 + 12 = 24
2
Sum of first 25 multiples of 44+8+12....100taking 4 common4(1+2+3+4....+25) = 4*325 =1300
4*n(n+1)
Well, the multiples of 8 go "8, 16, 24...etc." The first four multiples of 8 over 20 are 24, 32, 40, and 48. i) 24 + 32 = 56 ii) 56 + 40 = 96 iii) 96 + 48 = 144 Therefore the sum is 144.
8, 12, 16 & 208 + 12 = 20
They are 8 and 16
8 = 2310 = 2*512 = 22*3LCM = 3*5*8 = 120So the two first common multiples of 8, 10, and 12 are 120 and 240.