(1 x 8) + (2 x 8) = (1 + 2) x 8
= 3 x 8
= 24
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Oh, what a happy little question! To find the sum of the first two multiples of 8, we simply add them together. So, 8 + 16 equals 24. Just like painting a beautiful landscape, math can be a joyful experience when we take it one step at a time.
To find the sum of the first two multiples of 8, we first identify the multiples of 8: 8, 16, 24, 32, and so on. The first two multiples are 8 and 16. Adding them together, 8 + 16 equals 24. Therefore, the sum of the first two multiples of 8 is 24.
Oh, dude, the first two multiples of 8 are 8 and 16. So, if you add them up, you get 24. It's like basic math, man.
Sum of the first 15 positive integers is 15*(15+1)/2 = 120 Sum of the first 15 multiples of 8 is 8*120 = 960
5 + 10+15+20=50 ans
Sum of first 25 multiples of 44+8+12....100taking 4 common4(1+2+3+4....+25) = 4*325 =1300
Well, the multiples of 8 go "8, 16, 24...etc." The first four multiples of 8 over 20 are 24, 32, 40, and 48. i) 24 + 32 = 56 ii) 56 + 40 = 96 iii) 96 + 48 = 144 Therefore the sum is 144.
8A + (8A+8) + (8A+16) = 888 24A + 24 = 888 ===> 24A = 864 ===> A = 36 The multiples are 8A, 8A+8, 8A+16 = 288, 296, 304. Sum = 888.