The prime factors of 200 are 2 x 5 x 2 x 5 x 2. All possible multiples of those are all of 200's divisors. If you calculate all the divisors and add them up you will get the sum of divisors for 200. If that sum is greater than 400, then 200 is abundant. Here are a few examples of 200's divisors: 200, 100, 2, 50, 4, 8, 25. Already those add up to 391... if there are any more then 200 is certainly abundant. Does 200 have any other divisors?
Look at the multiples of 6. The smallest and greatest multiples of 6 that can be divided evenly by 4 are 12 and 48. So the common multiples of 4 and 6 up to 50 are 12, 24, 36, and 48.
There are 200 of them. Starting with 45*23 = 1035 and all the multiples of 45 up to 45*222 = 9990.
4, 8, 12, 16, 20, 24, 28, 32, 36, 40 and just keep adding 4 until you get to 200.
The numbers up to 12 are 4,8,12,16,20,24,28,32,36,40,44,48.
4,8,12,16,20
The multiples of 4 up to 200 are 4, 8, 12, 16, 20 and just keep adding 4 until you get to 200.
Start with 4. Add 4. Keep on adding 4 until you get to 200.
There are none.
Their sum is 1200.
Sum of first 25 multiples of 44+8+12....100taking 4 common4(1+2+3+4....+25) = 4*325 =1300
25,20,5,30
The prime factors of 200 are 2 x 5 x 2 x 5 x 2. All possible multiples of those are all of 200's divisors. If you calculate all the divisors and add them up you will get the sum of divisors for 200. If that sum is greater than 400, then 200 is abundant. Here are a few examples of 200's divisors: 200, 100, 2, 50, 4, 8, 25. Already those add up to 391... if there are any more then 200 is certainly abundant. Does 200 have any other divisors?
Those are the even numbers: 2, 4, 6, 8, 10 and so on.
To find all the multiples of 4 up to 200, we can start by identifying the first multiple of 4, which is 4. Then, we can continue adding 4 to each subsequent multiple to find the rest. The multiples of 4 up to 200 are 4, 8, 12, 16, 20, and so on, up to 196. The last multiple of 4 before exceeding 200 is 196.
All multiples of 12 are also multiples of 6 and they all can be written as the sum of nine numbers.
5 + 10+15+20=50 ans