All multiples of 12 are also multiples of 6 and they all can be written as the sum of nine numbers.
4 + 8 + 12 = 24
Sum of first 25 multiples of 44+8+12....100taking 4 common4(1+2+3+4....+25) = 4*325 =1300
3 + 6 + 9 + 12 = 30
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900
6 + 12 + 18 + 24 + 30 + 36 = 126
Their sum is 1200.
24
Multiples of 12.
A common multiple of two integers 'x' and 'y', are the multiples of 'x' which are also multiples of 'y'.For your example, because 12 is itself a multiple of 4, ALL multiples of 12 are common multiples of 4 and 12.To prove my point, I will list out the multiples of both 4 and 12:multiples of 4:4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80,84,88,92,96, 100...multiples of 12:12,24,36,48,60,72,84,96...You can see here that every multiple of 12, is also a multiple of 4, thus all multiples of 12 are common multiples for 4 and 12.Also..a quick easy list:12,24,36,48,60,72,84,96and if you didn't read above, because 12 is a multiple of for, all multiples of 12 are a multiple of 4 .. simple!
4 and 12
8, 12, 16 & 208 + 12 = 20