0
What else can I help you with?
2 plus 4i - 7 plus 4i?
(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
What is the sum of two complex conjugate number?
Since the imaginary parts cancel, and the real parts are the same, the sum is twice the real part of any of the numbers. For example, (5 + 4i) + (5 - 4i) = 5 + 5 + 4i - 4i = 10.
Find the conjugate of 8 plus 4i.?
The conjugate of a complex number is obtained by changing the sign of its imaginary part. For the complex number (8 + 4i), the conjugate is (8 - 4i).
What is x squared plus 80 equals 0?
It's a second degree equation in 'x' that has no real solution. No real number in the place of 'x' can make that equation a true statement. There are only two "imaginary" numbers that 'x' can be: + 4i sqrt(5) - 4i sqrt(5)
12 plus 8 plus 4 plus 0 plus -4 in summation notation?
4Σ (12 - 4i)i=0
2 plus 4i - 7 plus 4i?
(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
What is the conjugate of -6 plus 4i?
-6-4i.
What is the sum of 6 - 4i and 2 4i?
Add the real and the imaginary parts separately.
Find the absolute value of the complex number z equals 3 plus 4i?
('|x|' = Absolute value of x) |3+4i| = √(32 + 42) = √(9+16) = √25 = 5 Thus |3+4i| = 5.
What is the sum of two complex conjugate number?
Since the imaginary parts cancel, and the real parts are the same, the sum is twice the real part of any of the numbers. For example, (5 + 4i) + (5 - 4i) = 5 + 5 + 4i - 4i = 10.
What is the complex form of 4 plus 4i plus 4 plus 6i?
the problem: what is 4 + 4i + 4 + 6i what you do is add the real and imaginary parts, thus: 4+4 and 4i+6i = 8+10i answer.
What is the conjugate of 3 plus 4i?
When finding the conjugate of a binomial, you just reverse the sign. So the conjugate of 3+4i is 3-4i.
How do you factor xsquared plus 16?
(x - 4i)(x + 4i) where i is the square root of -1
What is the sum of (7 plus 3i) plus (8 plus 9i)?
(7 + 3i) + (8 + 9i) = (7 + 8) + (3i + 9i) = (7 + 8) + (3 + 9)i = 15 + 12i Which can also be written as: 15 + 12i = 3(5 + 4i).
How do you solve 9 plus 4i quantity squared?
(9 + 4i)^2 = 9^2 + (2)(9)(4i) +i^2 substitute i^2 for -1; = 81 + 72i -1 = 80 + 72i
What is x squared plus 80 equals 0?
It's a second degree equation in 'x' that has no real solution. No real number in the place of 'x' can make that equation a true statement. There are only two "imaginary" numbers that 'x' can be: + 4i sqrt(5) - 4i sqrt(5)
Find the complex fourth root of 256i Express your answer in a plus bi form?
The four roots of 4√256 are {4, -4, 4i, and -4i}. Note that two of them are real numbers and the other two are pure imaginary, therefore 0 + 4i is the same as just 4i
