0
What else can I help you with?
7 times the sum of x and s?
=7(x+s)
What positive number added to its reciprocal gives the maximum sum?
To find the positive number ( x ) that, when added to its reciprocal ( \frac{1}{x} ), gives the maximum sum, we can express the sum as ( S = x + \frac{1}{x} ). By using calculus, we can determine that this function reaches its minimum at ( x = 1 ), which means that the maximum sum occurs symmetrically around that point. Therefore, the maximum sum ( S ) occurs at ( x = 1 ), giving ( S = 1 + 1 = 2 ).
What is the sum of all numbers from 1 to 25 including in between?
There is a formula to calculate this sum. It is, S = ½n(n + 1) In this question, n = 25 so the sum of the numbers from 1-25 is, ½ x 25 x 26 = 325
What is the sum of all integers not greater than 10000 that are not divisible by 7?
This is easiest to answer by summing all the numbers 1-10000 and subtracting the sum of the multiples of 7 (7, 14, 21, ..., 9996). The sum of a series is: S = (first + last) x number_of_terms / 2 For for 1-10000, the sum is: S1 = (1 + 10000) x 10000 / 2 = 10001 x 5000 = 50005000 For the multiples of 7 the sum is: S2 = (7 + 9996) x 1428 / 2 = 10003 x 714 = 7142142 So the sum of all integers not greater than 10000 that are not divisible by 7 is: S = S1 - S2 = 50005000 - 7142142 = 42,862,858
Write the sum of x and -7?
x-7
7 times the sum of x and s?
=7(x+s)
The sum of a number and its square is 6 Find the number?
There are two solution: -3 and +2.
Sum of geometric series using c program?
there are different ways of writing dis program... 1+x+(x*x)+(x*x*x*)+....has a formula for its sum... the sum for a geometric series with a as initial value and x as common ratio is (a*(pow(r,n)-1))/(r-1).... where a=1;r=x.. accept the values of x and n through keyboard remember to take x as a float value!! apply the formula and be careful about the parantheses. happy programming!!!
Formula for s in statistics?
s=sample standard deviation s=square root (Sum(x-(xbar))2 /(n-1) Computing formula (so you don't have to find the mean and the distance from the mean over and over): square root(Sxx /(n-1)) Sxx= Sum(x2) - ((Sum(x))2/n)
Twice the sum of x and y and The sum of twice x and y?
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
What is the sum of all numbers from 1 to 25 including in between?
There is a formula to calculate this sum. It is, S = ½n(n + 1) In this question, n = 25 so the sum of the numbers from 1-25 is, ½ x 25 x 26 = 325
What is the sum of all integers not greater than 10000 that are not divisible by 7?
This is easiest to answer by summing all the numbers 1-10000 and subtracting the sum of the multiples of 7 (7, 14, 21, ..., 9996). The sum of a series is: S = (first + last) x number_of_terms / 2 For for 1-10000, the sum is: S1 = (1 + 10000) x 10000 / 2 = 10001 x 5000 = 50005000 For the multiples of 7 the sum is: S2 = (7 + 9996) x 1428 / 2 = 10003 x 714 = 7142142 So the sum of all integers not greater than 10000 that are not divisible by 7 is: S = S1 - S2 = 50005000 - 7142142 = 42,862,858
Write the sum of x and -7?
x-7
What is the difference between twice the sum of x and y and the sum of twice x and y?
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
If A equals 1 and Z equals 26 what is the sum of the letters in Xmas?
X = 24 M = 13 A = 1 S = 19 Sum = 57
What is the formula for finding the sum of angles?
Subtract the number of sides of the polygon by two then multiply it by 180Formula:Interior angle sum = (s-2) x 180 (With s being the number of sides the polygon has.
What is the method for finding the sum of 10 consecutive numbers?
The question, as asked, has no answer since there is no such thing as a consecutive number. Given any two numbers there is an infinity of numbers between them so non can be consecutive. However, I assume you meant consecutive INTEGERS, though there is a huge difference between integers and numbers. There are several methods. One of the simplest is as follows: Suppose the numbers are x, x+1, x+2, ... The last of the 10 will be x+9 Let their sum be S So S = x + (x+1) + (x+2) + ... + (x+9) Rewriting the 10 numbers in reverse order, S = (x+9) + (x+8) + (x+7) + ... + x Take the first number on the right hand side of each equation. Their sum is x + (x+9) = x+10. Take the second number on the right hand side of each equation. Their sum is (x+1) + (x+9) = x+10. Take the third number on the right hand side of each equation. Their sum is (x+2) + (x+8) = x+10. etc. Thus you have 10 pairs of numbers and each pair sums to x+10. So if you add the two equations, you get 2*S = 10*(x+10) or S = 5*(x+10). The result can be generalised as follows: The sum of k consecutive integers, from x to x+k-1, is k*(x+k)/2
