Assuming the base is square, then:
The area of the two bases = 2 x 8 x 8 = 128 cm
The area of the four side areas = 4 x 8 x 12 = 384 cm
Total area = 128 + 384 = 512 cm
Such a pyramid cannot exist. If it is a regular pyramid with side length 8, its slant height MUST be less than 8. In fact, it is approx 6.39.
The surface area is quadrupled.
Do length X height for one side. Then multiply that by 6 because there are 6 sides, and it is a cube, so each side is equal.
Side length is 8 meters.
(length of side)2 X 6 [or (length of side) X (length of side) X 6]
120
6 centimetres( to find surface area one must multiply height by height, width by width and length by length. Then you must add the products together and you get the surface area. To get the side lengths from a surface area you must reverse and divide it by 3[height,length and width]. In your case that would be 18. Then you must find a number that when multiplied by 3 equals the quotient of the first division{18} and there you have it 6). This only works on cubes.
The surface area can not be found from this information.
Base * height is surface area or (bh)
Total surface area= 1/2 times the perimeter of the base times the slant height plus the area of the base Lateral surface area= 1/2 times the perimeter times the slant height
PerimeterThe perimeter of a polygon is the sum of the lengths of all its sides.What is the perimeter of a square having side-length 74 cm? Since a square has 4 sides of equal length, the perimeter of the square is 74 + 74 + 74 + 74 = 4 × 74 = 296.
Such a pyramid cannot exist. If it is a regular pyramid with side length 8, its slant height MUST be less than 8. In fact, it is approx 6.39.
The surface area is quadrupled.
Do length X height for one side. Then multiply that by 6 because there are 6 sides, and it is a cube, so each side is equal.
If you know the length of a side (a) , the surface area is 6a2
Side length is 8 meters.
(length of side)2 X 6 [or (length of side) X (length of side) X 6]