The surface area is quadrupled.
if length and width are doubled then the volume should mulitiply by 8
It quadruples.
if length is doubled then resistivity increases&when area is doubled resistivity decreases.
When the dimensions of a cube are doubled, each side length increases from ( s ) to ( 2s ). The surface area of a cube is calculated as ( 6s^2 ); therefore, the new surface area becomes ( 6(2s)^2 = 6 \times 4s^2 = 24s^2 ). This shows that the new surface area is four times greater than the original surface area of ( 6s^2 ). Hence, when the dimensions are doubled, the surface area indeed increases by a factor of four.
When both the length and width of an original rectangle are doubled, the area increases by a factor of four. This is because the area of a rectangle is calculated by multiplying its length by its width. If the original dimensions are ( l ) (length) and ( w ) (width), then the new area becomes ( (2l) \times (2w) = 4lw ), which is four times the original area.
if length and width are doubled then the volume should mulitiply by 8
It quadruples.
Assuming no change in the width, yes.
Area = length*width new Area = 2 * length * width Area is doubled
if length is doubled then resistivity increases&when area is doubled resistivity decreases.
The change in the surface area depends on the shape. The volume will double.
The surface area of the 'wall' doubles, but the base areas remain the same.
The Area of a square can be written as it's side length^2, orA = s^2if the side length is doubled, then s' is 2s.A' = (s')^2A' = (2s)^2A' = 4s^2 = 4*AWhen the side length is doubled, the area increases by a factor of 4
When the dimensions of a cube are doubled, each side length increases from ( s ) to ( 2s ). The surface area of a cube is calculated as ( 6s^2 ); therefore, the new surface area becomes ( 6(2s)^2 = 6 \times 4s^2 = 24s^2 ). This shows that the new surface area is four times greater than the original surface area of ( 6s^2 ). Hence, when the dimensions are doubled, the surface area indeed increases by a factor of four.
When both the length and width of an original rectangle are doubled, the area increases by a factor of four. This is because the area of a rectangle is calculated by multiplying its length by its width. If the original dimensions are ( l ) (length) and ( w ) (width), then the new area becomes ( (2l) \times (2w) = 4lw ), which is four times the original area.
this is incorrect -- quick example.. 2"x2"x2" cube -- will have a surface area on each side of 4"sq (2x2=4) --- now make that 4"x4"x4" -- this cube will have a surface area on each side of 16"sq (4x4=16)
Surface Area becomes 4 times the original when its edges are doubled because Suraface area = (edge)^2