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How does the surface area of a rectangular prism change when the length and width and height are doubled?
if length and width are doubled then the volume should mulitiply by 8
What do you think happens to the surface area of a rectangular prism when each length is doubled?
It quadruples.
How does resistivity vary if length and area are doubled?
if length is doubled then resistivity increases&when area is doubled resistivity decreases.
If all the dimensions of a cube are doubled the surface area is four times greater?
When the dimensions of a cube are doubled, each side length increases from ( s ) to ( 2s ). The surface area of a cube is calculated as ( 6s^2 ); therefore, the new surface area becomes ( 6(2s)^2 = 6 \times 4s^2 = 24s^2 ). This shows that the new surface area is four times greater than the original surface area of ( 6s^2 ). Hence, when the dimensions are doubled, the surface area indeed increases by a factor of four.
What happens to the surface area of rectangular prism when measurements are doubled?
When the measurements of a rectangular prism are doubled, the surface area increases by a factor of four. This is because surface area is calculated using the formula (2(lw + lh + wh)), where (l), (w), and (h) are the length, width, and height. Doubling each dimension (length, width, and height) results in each area term being multiplied by four, leading to a total surface area that is four times larger than the original.
How does the surface area of a rectangular prism change when the length and width and height are doubled?
if length and width are doubled then the volume should mulitiply by 8
What do you think happens to the surface area of a rectangular prism when each length is doubled?
It quadruples.
If the length of a rectangle is doubled does the area double?
Assuming no change in the width, yes.
What happens to the area of a rectangle if one side is doubled?
Area = length*width new Area = 2 * length * width Area is doubled
How does resistivity vary if length and area are doubled?
if length is doubled then resistivity increases&when area is doubled resistivity decreases.
What happens to the surface area and volume when the height of a three-dimensional solid is doubled?
The change in the surface area depends on the shape. The volume will double.
What happens to the surface area of a cylinder if the height is doubled and the diameter of the base is not change?
The surface area of the 'wall' doubles, but the base areas remain the same.
If the length of a square is doubled how is the area affected?
The Area of a square can be written as it's side length^2, orA = s^2if the side length is doubled, then s' is 2s.A' = (s')^2A' = (2s)^2A' = 4s^2 = 4*AWhen the side length is doubled, the area increases by a factor of 4
If all the dimensions of a cube are doubled the surface area is four times greater?
When the dimensions of a cube are doubled, each side length increases from ( s ) to ( 2s ). The surface area of a cube is calculated as ( 6s^2 ); therefore, the new surface area becomes ( 6(2s)^2 = 6 \times 4s^2 = 24s^2 ). This shows that the new surface area is four times greater than the original surface area of ( 6s^2 ). Hence, when the dimensions are doubled, the surface area indeed increases by a factor of four.
What is the surface area of a cube if its edges are doubled?
Surface Area becomes 4 times the original when its edges are doubled because Suraface area = (edge)^2
If the length of each side of a cube is doubled is the surface area doubled?
this is incorrect -- quick example.. 2"x2"x2" cube -- will have a surface area on each side of 4"sq (2x2=4) --- now make that 4"x4"x4" -- this cube will have a surface area on each side of 16"sq (4x4=16)
How are the area and volume each affected if the side length is doubled and Cubed?
If the side length of a cube is doubled, the area of each face increases by a factor of four, since area is proportional to the square of the side length (A = s²). Therefore, the total surface area increases by a factor of four as well. When the side length is cubed, the volume increases by a factor of eight, since volume is proportional to the cube of the side length (V = s³). Thus, doubling the side length results in a surface area that is four times greater and a volume that is eight times greater.
