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What is the value for x in the following systems of equations x-y equals 5 2x plus y equals 7?
x - y = 52x + y = 7 (use the substitution method)y = x - 52x + y = 7 (substitute x - 5 for y into the second equation)2x + y = 72x + x - 5 = 73x = 12x = 4Thus x = 4 satisfies both the equations of the system.
Solve this equation using addition method x subtract y equals 6 and 3y equals x plus 22?
x - y = 63y = x + 22you need to solve these equations simultaneously.first get all your x's and y's on the same side.x - y = 63y - x = 22if you add these two equations together, the x's will cancel as one is positive and the other negative.x - y + 3y - x = 22 + 62y = 28y = 14then substitute y is 14 into one of the original equations to find xx - 14 = 6x = 20
What is the value of x for the equations x-y equals 120 and x plus y equals 150?
x-y = 120 x+y = 150 add equations: 2x = 270 x = 135 y = 15
What is the answer to the systems of equations x minus y equals 10 x plus y equals 4?
X - Y = 10 X + Y = 4 -------------------+ ( add them ) 2X = 14 X = 7 ----------find Y in one of the equations; top looks good 7 - Y = 10 - Y = 3 Y = - 3 ---------------check both equations for consistency 7 - (- 3) = 10 7 + 3 = 10 10 = 10 ------------checks in top 7 + (- 3) = 4 7 - 3 = 4 4 = 4 ------------checks and is consistent (7, - 3) ( the answer )
What is a method used for solving systems of equation in which one of the equations is substituted into another?
It is called substitution. Solve one of the equations for a single variable and substitute it into the other. x+y=10 y=10-x 2x-y=-4 2x-(10-x)=-4 2x-10+x=-4 3x-10=-4 3x=6 x=2 x+y=10 (2)+y=10 y=8
