Without any equality signs the given terms can't be considered to be equations but if you mean x+y = 10 and x-y = 6 then the value of x is 8 and the value of y is 2 and both equations intersect at (8, 2) on the Cartesian plane.
Without any equality signs they can't be considered to be equations.
This is a system of equations:-x + 5y = 10-5x + 2y = 27Multiply the first equation by 5.-5x + 25y = 50Subtract the 2 equations:23y = 23Solve:y = 1-x + 5(1) = 10-x = 5x = -5Thus, the ordered pair is (-5, 1).
No because there are no equations there to choose from.
10c + 10The only common factor is 10, and this can be divided out, resulting in:10(c+1)
It looks like you have 2 simultaneous equations with 2 variables:4x + 8y = 20 and -4x + 2y = -30. Solution is {x=7, y = -1}.One way to solve:Add the two equations together, combining like terms: (4x - 4x) + (8y + 2y) = 20-30 --> 0 + 10y = -10 --> y = -1. Substitute this into either of the original equations and solve for x=7, then check in the other equation to make sure you calculated correctly.
There are two equations in the question, not one. They are the equations of intersected lines, and their point of intersection is their common solution.
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Without any equality signs the given terms can't be classed as equations.
Without any equality signs they can't be considered to be equations.
Without any equality signs the given terms can't be considered to be equations
you need 2 equations to solve for 2 variables
Solving the simultaneous equations works out as x = -2 and y = -2 So the lines intersect at: (-2, -2)
No, there is no common ratio for the given number.
Yes, because neither variable has an exponent different from ' 1 '.
They have n in common.
Without any equality signs the given terms can't be considered to be equations.