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Equation of circle: x^2 +10x +y^2 -2y -39 = 0

Completing the squares: (x+5)^2 +(y-1)^2 = 65

Center of circle: (-5, 1)

Point of contact: (3, 2)

Slope of radius: 1/8

Slope of tangent: -8

Tangent equation: y-2 = -8(x-3) => y = -8x+26

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Q: What is the tangent equation of the circle x2 plus 10x plus y2 -2y -39 equals 0 at the coordinate of 3 2?
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