the sum of three consecutive numbers is 216. What are the three numbers?
3 + 6 + 12 = 21 3 x 6 x 12 = 216
23 x 33 = 216
6 + 7 + 8 = 216 x 7 x 8 = 336Therefore, the three numbers are 6, 7 and 8.
divide 216 by 3 (72) subtract 1 and add 1 71, 72 and 73
216 = 2x2x2x3x3x3
the sum of three consecutive numbers is 216. What are the three numbers?
3 + 6 + 12 = 21 3 x 6 x 12 = 216
71,72,73 :)
23 x 33 = 216
71 + 72 + 73 = 216
6 + 7 + 8 = 216 x 7 x 8 = 336Therefore, the three numbers are 6, 7 and 8.
As a product of its prime factors expressed in exponents it is: 23*33 = 216
divide 216 by 3 (72) subtract 1 and add 1 71, 72 and 73
The numbers are 71, 72 and 73.
For 216 the numbers are 70, 72 and 74. For 238 the numbers are 58, 59, 60 and 61.
x+x+1+x+2=216 3x+3=216 3x=213 71,72,73