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What is the total mass of rn 222 remaining in an original 160 mg sample of rn 222 after 19.1 days?
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How many days remaining from February 5 2008 up to July 15 2008?
121 days
How many days are in august and how many days are in September?
There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.
How much of radioactive substance remains after 15 hours if it's half life is 5 hours?
The half-life of a radioactive substance is the time that it takes for half of the atoms to decay. With a half-life of 10 days, half has decayed in this time. After 20 days, a further 10 days/another half life, a further half of the remainder has decayed, so 1/4 of the original material remains, 1/4 of 15g is 3.75 grams. This is the amount of original radioactive substance remaining, but it’s daughter isotope ( what the decay has produced ) is also present, so the original sample mass is effectively constant, especially in a sealed container. Even in an unsealed container, and assuming alpha ( helium nucleii) emission, a drop in mass per radioactive atom of 4 Atomic Mass units, compared with the original atom of, say 200 amu is only 2% mass decrease, less for heavier decaying nucleii.
Why does March have 5 weeks?
There are 31 days in March. March in 2015 only has four full weeks of 7 days, with 3 days remaining.
How long is 30 days in weeks?
4 weeks and 2 days. 30 divided by 7 equals 4 with 2 remaining.
What is the total mass of 222Rn remaining in an original 160-milligram sample of 222Rn after 19.1 days?
To find the remaining mass of a radioactive isotope after a certain time, you can use the radioactive decay formula: [M_{\text{final}} = M_{\text{initial}} \times \left( \frac{1}{2} \right)^{\frac{t}{t_{1/2}}}] Given that the half-life of (^{222}\text{Rn}) is 3.8 days, and the initial mass is 160 milligrams, you can substitute these values into the formula to find the final mass.
A sample of radioactive isotope has a halflife of 1 day how much of the original sample will be left at the end of the fourth day?
If a sample of radioactive material has a half-life of one week the original sample will have 50 percent of the original left at the end of the second week. The third week would be 25 percent of the sample. The fourth week would be 12.5 percent of the original sample.
The half life of Rn-222 is 4 daysWhat was the original mass of a sample of this isotope remains after 21 hrs?
To determine the original mass that remains after 21 hours, we first convert 21 hours to days (21 hours/24 hours per day = 0.875 days). Then, we can calculate the fraction of Rn-222 remaining after this time by raising 1/2 to the power of (0.875/4). This fraction can then be multiplied by the original mass to find the mass remaining.
How much of an 80-milligram sample of Iodine-131 would be left after 32 days?
After 32 days, approximately 5 milligrams of the 80-milligram sample of Iodine-131 would be left. Iodine-131 has a half-life of about 8 days, so after each 8-day period, half of the remaining sample will decay.
The half life of iron 59 is 44.5 days how much of 2mg sample will remain after 133.5 days?
After 133.5 days, there will be 0.125 mg of the 2 mg sample of iron-59 remaining. This can be calculated by taking into account each half-life period (44.5 days) and calculating the remaining amount after 3 half-lives (133.5 days).
The half-life of Au-198 is 2.7 days When there are 800 atoms of Au-198 in a sample a scientist starts a stopwatch The scientist stops the stopwatch at 8.1 days there are atoms of Au-198 re?
At 2.7 days, half of the 800 atoms (400 atoms) would have decayed. At 8.1 days, three half-lives have passed, so only ( \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8} ) of the original sample remains. Therefore, there are 100 atoms of Au-198 remaining in the sample after 8.1 days.
The half-life of radon-222 is about four days. After how many days is the amount of radon-222 equal to one-sixteenth of its original amount?
Let's step through the half-life of radon to see how it works. Radon-222 starts at full strength. In four days (its half-life), it is at half strength. In four more days, it is again at half strength (of the half strength) for a total of 1/4 strength. In four more days, it is again half the strength (of the 1/4 strength) for a total of 1/8 strength. In four more days, it is another half life weaker, for a total of 1/16 strength. In 16 days, this isotope of radon has just 1/16th the original radiation.
How much of a 100 g sample of thorium 234 will be unchanged after 48.2 days?
Thorium-234 has a half-life of 24.1 days. After 48.2 days, half of the sample will remain unchanged. Therefore, 50% of the original 100 g sample, which is 50 g, will be unchanged after 48.2 days.
If a 100 g sample of a radioactive element decays to 25 g in 4 days what is the half-life of the element?
If a radioactive sample contains 1.25g of an isotope with a half-life of 4.0 days, then 0.625g (1/2) of the isotope will remain after 4.0 days, 0.3125g (1/4) after 8.0 days, 0.15625g (1/8) after 12.0 days, etc. AT = A0 2(-T/H)
What is the half life of a radioactive isotope if it takes 6.2 days for a 72 gram sample to decay to 18grams?
18 grams are one fourth of the original sample mass of 72 grams. Accordingly, the half life is 6.2/4 = 1.55 days.
Thorium-234 has a half-life of 24.1 days. How much of a 100-g sample of thorium-234 will be unchanged after 48.2 days?
After 48.2 days (two half-lives), one-fourth (25%) of the original thorium-234 sample will remain unchanged. Therefore, 25 g of the 100-g sample will be unchanged after 48.2 days.
Bismuth 210 has half life of 5 days and a sample originally has a mass of 800mg What is the formula for mass remaining after t days?
The mass can be determined with the formula m=800(.5)^(t/5)
