So, if we see the basic equation y=mx+b, we see that m=2, and b=1. If you look closely, this is basic rotation and translation of the original graph. First, I would translate the "mother graph" (y=mx) and then translate one up. Then, we would rotate the graph to the right two units.
The translation is vertical if the added term is outside the main function and horizontal if it is inside it, next to the x. For example, y = x^2 represents a parabola, with its lowest point at (0,0). If we have the equation y = x^2 + 2 then we have translated the parabola up two units -- its lowest point is now x = 0, y = 2. But if we write y = (x + 2)^2, then we are translating two units to the left, and the lowest point is x = -2, y = 0.
The graph would be translated upwards by 2 units.
The ordered pair IS the coordinates on the graph. If you have the ordered pair (1,2) that means the value of x is 1 and the value of y is 2, so to get to that point on a graph from the origin (center) you would move right 1 unit and up 2 units.
Translation is moving a graph to the left or right, up or down (or both). Given a quadratic equation of the form y = ax^2 + bx + c, if you substitute u = x - p and v = y - q then the graph of v against u will be the same as the x-y graph, translated to the left by p and downwards by q.
Y=|x+2|
the translation of 2 is the one that triangle moves by 4 units right and 8 units up
If you we're at the point (8,-2) and you went 5 units right and 2 units up, you'd be at (13,0).
(x,y) > (x + 8, y + 2)
f(x) cannnot be a graph of itself translated down by anything other than 0 units.
So, if we see the basic equation y=mx+b, we see that m=2, and b=1. If you look closely, this is basic rotation and translation of the original graph. First, I would translate the "mother graph" (y=mx) and then translate one up. Then, we would rotate the graph to the right two units.
The translation is vertical if the added term is outside the main function and horizontal if it is inside it, next to the x. For example, y = x^2 represents a parabola, with its lowest point at (0,0). If we have the equation y = x^2 + 2 then we have translated the parabola up two units -- its lowest point is now x = 0, y = 2. But if we write y = (x + 2)^2, then we are translating two units to the left, and the lowest point is x = -2, y = 0.
The graph of is shifted 3 units down and 2 units right. Which equation represents the new graph?
The graph would be translated upwards by 2 units.
(2,1)
The ordered pair IS the coordinates on the graph. If you have the ordered pair (1,2) that means the value of x is 1 and the value of y is 2, so to get to that point on a graph from the origin (center) you would move right 1 unit and up 2 units.
y=x-2