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Graph the equation y equals 2x plus 1?
So, if we see the basic equation y=mx+b, we see that m=2, and b=1. If you look closely, this is basic rotation and translation of the original graph. First, I would translate the "mother graph" (y=mx) and then translate one up. Then, we would rotate the graph to the right two units.
How do you know if the translation of a graph is vertical or horizontal?
The translation is vertical if the added term is outside the main function and horizontal if it is inside it, next to the x. For example, y = x^2 represents a parabola, with its lowest point at (0,0). If we have the equation y = x^2 + 2 then we have translated the parabola up two units -- its lowest point is now x = 0, y = 2. But if we write y = (x + 2)^2, then we are translating two units to the left, and the lowest point is x = -2, y = 0.
How would you translate the graph of y-x2 to produce the graph of y-(x-2)2?
To translate the graph of ( y = -x^2 ) to produce the graph of ( y = -(x-2)^2 ), you would shift the graph 2 units to the right. This transformation occurs because the expression inside the parentheses, ( (x-2) ), indicates a horizontal shift. The negative sign in front of the squared term indicates that the parabola opens downward, which remains unchanged in the translation. Thus, the vertex moves from the origin (0, 0) to the new vertex at (2, 0).
If y12x-2 were changed to y12x how would the graph of the new function compare to the original?
The graph would be translated upwards by 2 units.
How shift x graph up?
To shift a graph of a function ( f(x) ) upward by ( k ) units, you simply add ( k ) to the function. The new function becomes ( f(x) + k ). For example, if the original function is ( f(x) = x^2 ) and you want to shift it up by 3 units, the new function would be ( f(x) + 3 = x^2 + 3 ). This transformation moves every point on the graph up by the specified amount.
Which of the following equations is the translation 2 units down of the graph of y x?
Y=|x+2|
What translation moves a triangle 4 units to the right and 8 units up?
the translation of 2 is the one that triangle moves by 4 units right and 8 units up
What is the image point of (8,−2)(8,-2)(8,−2) after a translation right 5 units and up 2 units?
If you we're at the point (8,-2) and you went 5 units right and 2 units up, you'd be at (13,0).
Which rule describes a translation that is 8 units to the right and 2 units up?
(x,y) > (x + 8, y + 2)
Graph the equation y equals 2x plus 1?
So, if we see the basic equation y=mx+b, we see that m=2, and b=1. If you look closely, this is basic rotation and translation of the original graph. First, I would translate the "mother graph" (y=mx) and then translate one up. Then, we would rotate the graph to the right two units.
If f(x) is the graph of f(x) translated down 2 units?
f(x) cannnot be a graph of itself translated down by anything other than 0 units.
How do you know if the translation of a graph is vertical or horizontal?
The translation is vertical if the added term is outside the main function and horizontal if it is inside it, next to the x. For example, y = x^2 represents a parabola, with its lowest point at (0,0). If we have the equation y = x^2 + 2 then we have translated the parabola up two units -- its lowest point is now x = 0, y = 2. But if we write y = (x + 2)^2, then we are translating two units to the left, and the lowest point is x = -2, y = 0.
How would you translate the graph of y-x2 to produce the graph of y-(x-2)2?
To translate the graph of ( y = -x^2 ) to produce the graph of ( y = -(x-2)^2 ), you would shift the graph 2 units to the right. This transformation occurs because the expression inside the parentheses, ( (x-2) ), indicates a horizontal shift. The negative sign in front of the squared term indicates that the parabola opens downward, which remains unchanged in the translation. Thus, the vertex moves from the origin (0, 0) to the new vertex at (2, 0).
Which is the exponential form of log 8 x equals 3?
The graph of is shifted 3 units down and 2 units right. Which equation represents the new graph?
If y12x-2 were changed to y12x how would the graph of the new function compare to the original?
The graph would be translated upwards by 2 units.
what is the image point of (0,4) after a translation right 2 units and down 3 units?
(2,1)
How shift x graph up?
To shift a graph of a function ( f(x) ) upward by ( k ) units, you simply add ( k ) to the function. The new function becomes ( f(x) + k ). For example, if the original function is ( f(x) = x^2 ) and you want to shift it up by 3 units, the new function would be ( f(x) + 3 = x^2 + 3 ). This transformation moves every point on the graph up by the specified amount.
