To find the true vertical depth of a well that is 10 meters long at a 45-degree angle, you can use trigonometry. The true vertical depth (TVD) can be calculated using the sine function: TVD = length × sin(angle). Thus, TVD = 10 meters × sin(45°) = 10 meters × √2/2 ≈ 7.07 meters. Therefore, the true vertical depth is approximately 7.07 meters.
A fall of 4 degrees over 1 meter refers to a slope or incline where the vertical drop is 4 degrees relative to the horizontal. To calculate the vertical drop, you can use the tangent function: the vertical drop is approximately 0.07 meters (or 7 centimeters) over 1 meter of horizontal distance. This represents a gentle slope, as 4 degrees is a small angle.
1 square meter. The depth is irrelevant in this question.
50x50x5mm sleel angle per meter lenth in weight kilo gramm ?
To find the acute angle of the ramp, you can use the sine function in trigonometry. The sine of the angle ( \theta ) is equal to the opposite side (height) divided by the hypotenuse (ramp length): ( \sin(\theta) = \frac{0.643}{1} ). Calculating this gives ( \theta = \arcsin(0.643) ), which is approximately 40.0 degrees. Thus, the acute angle of the ramp is about 40 degrees.
To calculate the fall (or rise) for an 11-degree roof over 1 meter, you can use the tangent of the angle. The fall can be calculated as: fall = 1 meter * tan(11 degrees). This gives approximately 0.193 meters, or 19.3 centimeters of fall over 1 meter of horizontal distance.
A fall of 4 degrees over 1 meter refers to a slope or incline where the vertical drop is 4 degrees relative to the horizontal. To calculate the vertical drop, you can use the tangent function: the vertical drop is approximately 0.07 meters (or 7 centimeters) over 1 meter of horizontal distance. This represents a gentle slope, as 4 degrees is a small angle.
Using trigonometry and the tangent ratio its height is 135 meters to the nearest meter.
2.2
To calculate the vertical drop over a given horizontal distance due to a slope, we use the formula: vertical drop = horizontal distance * tan(slope angle). Given a 3-degree slope over 1 meter, the vertical drop would be 1 meter * tan(3 degrees), which is approximately 0.0524 meters or 5.24 centimeters. This means that for every 1 meter of horizontal distance, the elevation would decrease by about 5.24 centimeters.
The alternate angle is 32 degrees and so 20/tan(32) = 32 meters
a creep meter measures vertical movement and a tilt meter measures horizontal movement. Hope my answer works for you thanks
Well by the angle being at a certain angle it will launch sometime more then one meter and if the angle was a right angle then it will launch 350CM.
1 square meter. The depth is irrelevant in this question.
1 meter cubed
the creep meter
It is: 27.35 degrees rounded to two decimal places
.02mm