Find two consecutive numbers with the value of 4160
The numbers are 64 and 65.
The numbers are 64 and 65.
the answer is 905 and 906
Let the page numbers be x and x+1. The product of two consecutive numbers is x(x+1). Given that the product is 4160, we have the equation x(x+1) = 4160. By solving this quadratic equation, we find that the page numbers are 64 and 65.
Find two consecutive numbers with the value of 4160
64 x 65 = 4160
The numbers are 64 and 65.
The numbers are 64 and 65.
the answer is 905 and 906
Let the page numbers be x and x+1. The product of two consecutive numbers is x(x+1). Given that the product is 4160, we have the equation x(x+1) = 4160. By solving this quadratic equation, we find that the page numbers are 64 and 65.
Assuming you mean consecutive numbers are integers, then: The integers will be the two integers between which the square root of 4160 lies. Calculating the square root of 4160 using the "long" division method: ________6__4 _____---------- ___6|_41_60 _______36 _______--- __124|__560 _________496 _________---- __________64 The square root of 4160 is 64.<something>, thus it lies between 64 and 65, so: 4160 = 64 × 65
4160 - 800 = 3360
I think it would be .4160 but you will have to double check!
Answer: 4160 mi. = 6694.871 km
Answer: 4160 mi. = 6,694.871 km
4160 ÷ 21 = 198 with remainder 2