To find the value of (3y^2 + 2) when (y = -1), substitute (-1) for (y):
[ 3(-1)^2 + 2 = 3(1) + 2 = 3 + 2 = 5. ]
Thus, the value is (5).
(4y + 1)(3y + 2)
(3x + 3y)(x + y) = 3(x + y)2
0
y(3y^2 - 12y + 4)
x=1y=2x+3y=2*1 + 3y=5
The GCF is 3y^2.
(4y + 1)(3y + 2)
i think its 3y squared
what number is y?
(3x + 3y)(x + y) = 3(x + y)2
The term "3y squared" represents the product of 3 and y squared. This means you are multiplying the number 3 by the variable y raised to the power of 2. In mathematical terms, it can be written as 3y^2. This expression denotes 3 times y squared, where y is multiplied by itself.
0
y(3y^2 - 12y + 4)
x=1y=2x+3y=2*1 + 3y=5
The expression (2y(y + 1)(3y + 1)) cannot be simplified to a single numerical answer without knowing the value of (y). However, it can be expanded to (2y(y + 1)(3y + 1) = 2y(3y^2 + 4y + 1) = 6y^3 + 8y^2 + 2y). This represents a polynomial in terms of (y).
2x+3y=-1 and 5x-2y=-12 3y=-2x-1 and -2y=-5x-12 y=(-2/3)x-1/3 and y=(5/2)x+6 Substitute the first value of y into the second equation (-2/3)x-1/3=(5/2)x+6 (-19/6)x=19/3 x=-2 Plug this value of x into the first equation 2(-2)+3y=-1 -4+3y=-1 3y=3 y=1 Check your results by plugging x=-2 and y=1 into the second equation 5(-2)-2(1)=-12 -10-2=-12 -12=-12 This is correct, so the final answer is x=-2 and y=1
There are two simultaneous equations, so to solve for y, eliminate x: 1) 2x + 3y = 3 2) 4x - 3y = 9 Multiply equation (1) by 2 giving: 1) 4x + 6y = 6 2) 4x - 3y = 9 Next, subtract equation (2) from equation (1), giving: (4x - 4x) + (6y - -3y) = 6 - 9 → 9y = -3 → y = -1/3