To find the value of (3y^2 + 2) when (y = -1), substitute (-1) for (y):
[ 3(-1)^2 + 2 = 3(1) + 2 = 3 + 2 = 5. ]
Thus, the value is (5).
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(4y + 1)(3y + 2)
(3x + 3y)(x + y) = 3(x + y)2
0
y(3y^2 - 12y + 4)
x=1y=2x+3y=2*1 + 3y=5