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What is cos 60?
hi,the value of cos 60 is 1/2
What is cos-1 3?
The cosine function has an absolute value that cannot exceed 1. Therefore the is no angle x such that cos(x) = 3. That is, there is no angle x such that x = cos^-1(3).
How do you proof that there is one and only one value of theta makes cos of theta equals 1 true?
You cannot prove it because it is not true! cos(0) = 1 cos(2*pi) = 1 cos(4*pi) = 1 ... cos(2*k*pi) = 1 for all integers k or, if you still work in degrees, cos(0) = 1 cos(360) = 1 cos(720) = 1 ... cos(k*360) = 1 for all integers k
What is the minimum value that the function y equals cos x assumes?
Since the range of the cosine function is (-1,1), the function y = cos(x) assumes a minimum value of -1 for y.
Given that Sin x equals 0.8 and x is acute write down the value of Cos x?
cos2x = 1 - sin2x = 1 - 0.64 = 0.36 So cos x = +/- 0.6 Since x is acute, cos x is +ve, so cos x = 0.6
What is cos 60?
hi,the value of cos 60 is 1/2
What is the value of sin A plus cos Acos A (1-cos A) when tan A 815?
When tan A = 815, sin A = 0.9999992 and cos A = 0.0012270 so that sin A + cos A*cos A*(1-cos A) = 1.00000075, approx.
Value of cos 315?
cos 315 degrees is 4th quadrant same as cos (-45) degrees which is +0.7071
What is cos-1 3?
The cosine function has an absolute value that cannot exceed 1. Therefore the is no angle x such that cos(x) = 3. That is, there is no angle x such that x = cos^-1(3).
How do you proof that there is one and only one value of theta makes cos of theta equals 1 true?
You cannot prove it because it is not true! cos(0) = 1 cos(2*pi) = 1 cos(4*pi) = 1 ... cos(2*k*pi) = 1 for all integers k or, if you still work in degrees, cos(0) = 1 cos(360) = 1 cos(720) = 1 ... cos(k*360) = 1 for all integers k
What is the approximate value of cos C?
1-C2/2
What is the value of 1- cos x when x is small?
1 - cos x as x approaches 0. what is the cos of 0? It is 1. So as x approaches 0 cos x approaches 1. 1 - 1 = 0 So as it gets very small the solutions gets smaller.
If cos x equals 1 what is the value of sec x?
Secant x= 1/cosx So if cos x=1 ,we know that x=0 degrees ( or radians), so secant x is 1/cos (0)=1/1=1
What is the derivative of ln cos x?
The derivative of the natural log is 1/x, therefore the derivative is 1/cos(x). However, since the value of cos(x) is submitted within the natural log we must use the chain rule. Then, we multiply 1/cos(x) by the derivative of cos(x). We get the answer: -sin(x)/cos(x) which can be simplified into -tan(x).
What is the maximum value of cos square x - sin square x?
1
What is the value of cos 40 degrees?
The value of cos 40 degrees is approximately 0.766.
What is the maximum value that the graph of ycosx assume?
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
