The expression appears to be: (12-4t)/6
10
y2 - 36 does not have a value unless we know what y is. We can, however, factor this expression: it factors to (y + 6)(y - 6).
6
(3*5)+(6 to the power of 2)+54-5
The expression would be written as 16 The value of the expression is 1. 1 x 1 x 1 x 1 x 1 x 1 = 1
The expression appears to be: (12-4t)/6
10
y2 - 36 does not have a value unless we know what y is. We can, however, factor this expression: it factors to (y + 6)(y - 6).
4
6
(3*5)+(6 to the power of 2)+54-5
It would be 46656.
The vertex of this parabola is at 5 5 When the x-value is 6 the y-value is -1. The coefficient of the squared expression in the parabola's equation is -6.
It is simply x - 6. The expression cannot be evaluated because the value of x is not given.
This expression is invalid unless you left out parentheses in your question:20 = 2² ÷ 1 + 6 x 320 = 4 ÷ 1 + 6 x 320 = 4 + 6 x 320 = 4 + 1820 ≠ 22
6