It is 10.
Just substitute 4 in for X. 13 - 2(4) 13 - 8 = 5 ===
If x = 3, then x + 10 would be 3 + 10, which is 13.
4x^2 + 9 is a prime algebraic expression. Its numerical value may be prime of not - depending on the value of x.For x = 1, the value of the expression is 13 - a prime whereasfor x = 2, the value of the expression is 25 - not a prime.
13 x 10 = 130
It is 10.
Just substitute 4 in for X. 13 - 2(4) 13 - 8 = 5 ===
x+10>13 it wouldn't be x+10-13 ??
7
If x = 3, then x + 10 would be 3 + 10, which is 13.
4x^2 + 9 is a prime algebraic expression. Its numerical value may be prime of not - depending on the value of x.For x = 1, the value of the expression is 13 - a prime whereasfor x = 2, the value of the expression is 25 - not a prime.
It means that if you know the value of a variable, you replace every occurence of the variable with the value. For example, if x = 10, and you have the expression x2 + 5x - 3, you replace every x with 10, to get 102 + 5(10) - 3.It means that if you know the value of a variable, you replace every occurence of the variable with the value. For example, if x = 10, and you have the expression x2 + 5x - 3, you replace every x with 10, to get 102 + 5(10) - 3.It means that if you know the value of a variable, you replace every occurence of the variable with the value. For example, if x = 10, and you have the expression x2 + 5x - 3, you replace every x with 10, to get 102 + 5(10) - 3.It means that if you know the value of a variable, you replace every occurence of the variable with the value. For example, if x = 10, and you have the expression x2 + 5x - 3, you replace every x with 10, to get 102 + 5(10) - 3.
13 x 10 = 130
Well, isn't that a happy little math problem! When we have 18 and we take away a little x, we're left with a beautiful number. Just imagine x as a fluffy cloud floating away, and you'll find the answer in no time. Remember, there are no mistakes in math, just happy little accidents!
The base of log, if unspecified, is taken to be 10 so you would be finding the value of the logarithm of 5 to the base 10.This is the value x, such that 10^x = 5.
To evaluate the algebraic expression 7 + 5x for x = 10, you substitute the value of x into the expression. So, you get 7 + 5(10), which simplifies to 7 + 50. Therefore, the final answer is 57.
x + (13-10)