If we are not given the exact relationship between two variables, it is not possible to find the value of one variable corresponding to the value of the other variable. Let us solve it by the two following methods and see the difference.Method 1When x=3 then y=12i.e., y/x=12/3=4i.e., y=4xWhen x=7, then y=4*7=28Method 2When x=3 then y=12i.e., x+y=3+12=15i.e., y=15-xWhen x=7, y=15-7=8
if 2x + y = 7, what is the value of y when x = 3?
Jan 12 and Mike 3 ..... 12/3 = 4 and 12 + 3 = 15 Let Jan's age be x years and Mike's age be y years. Given that Jan is older than mike and the sum of their ages is 15. That implies x + y = 15. Also given that the quotient of their age is four. We know that Jan is older than mike. So, the quotient of their age is four implies x/y = 4. => x = 4y. We need to find the age of Jan. Substitute the value of x = 4y in the equation x + y = 15. x + y = 15 => 4y + y = 15 => 5y = 15 => y = 15/5 => y = 3. So, the age of Mike is 3 years. Substitute the value of y in the equation x + y = 15. x + 3 = 15 x = 15 - 3 x = 12 Jan is 12 years old.
y = 15 - 8x/3 y - 15 = -8x/3 15 - y = 8x/3 x = 3/5(15 - y) and so x = 9 - 3y/5
As y is inversely proportional to x, the equation relating x to y is given by: y = k/x where k is the constant of proportionality. Using this we can find expressions for the value of y when x = 2 and x = 6 in terms of k: x = 2 → y = k/2 x = 6 → y = k/6 The difference between these is k/2 - k/6 = 3k/6 - k/6 = 2k/6 = k/3 But this, we are told is 5; thus: k/3 = 5 → k = 15 Thus y = 15/x Now that we have found the equation relating x to y, we can plug in the value for x = 4 and find the value of y: The value for y when x = 4 is y = 15/4 = 3.75
If you mean: x+y = 30 and the value of y is 15 then the value of x is also 15
x is 0.8
It depends on the relationship between x and y.
If we are not given the exact relationship between two variables, it is not possible to find the value of one variable corresponding to the value of the other variable. Let us solve it by the two following methods and see the difference.Method 1When x=3 then y=12i.e., y/x=12/3=4i.e., y=4xWhen x=7, then y=4*7=28Method 2When x=3 then y=12i.e., x+y=3+12=15i.e., y=15-xWhen x=7, y=15-7=8
if 2x + y = 7, what is the value of y when x = 3?
Jan 12 and Mike 3 ..... 12/3 = 4 and 12 + 3 = 15 Let Jan's age be x years and Mike's age be y years. Given that Jan is older than mike and the sum of their ages is 15. That implies x + y = 15. Also given that the quotient of their age is four. We know that Jan is older than mike. So, the quotient of their age is four implies x/y = 4. => x = 4y. We need to find the age of Jan. Substitute the value of x = 4y in the equation x + y = 15. x + y = 15 => 4y + y = 15 => 5y = 15 => y = 15/5 => y = 3. So, the age of Mike is 3 years. Substitute the value of y in the equation x + y = 15. x + 3 = 15 x = 15 - 3 x = 12 Jan is 12 years old.
y = 15 - 8x/3 y - 15 = -8x/3 15 - y = 8x/3 x = 3/5(15 - y) and so x = 9 - 3y/5
If: 2x-3y = -15 and x = 4y Then: x = -12 and y = -3
As y is inversely proportional to x, the equation relating x to y is given by: y = k/x where k is the constant of proportionality. Using this we can find expressions for the value of y when x = 2 and x = 6 in terms of k: x = 2 → y = k/2 x = 6 → y = k/6 The difference between these is k/2 - k/6 = 3k/6 - k/6 = 2k/6 = k/3 But this, we are told is 5; thus: k/3 = 5 → k = 15 Thus y = 15/x Now that we have found the equation relating x to y, we can plug in the value for x = 4 and find the value of y: The value for y when x = 4 is y = 15/4 = 3.75
x is 45.
10
33/4