-32
x*y = k where k is a constant.When x = 9, y = 7 so k = 9*7 = 63 When x = 21, 21*y = 63 so y = 3.
y=3 y^3(y^3-y)= 3^3(3^3-3)= 27(27-3)= 27(24)=648
y = kx k = y/x = 21/-5 = - 21/5
y and ½z
When x = 3, y = 3*32 - 2*3 = 27 - 6 = 21
14
y = (3 X 8) - 5 = 21.
-32
x+y=27 x=14 27-14=y y=13
x*y = k where k is a constant.When x = 9, y = 7 so k = 9*7 = 63 When x = 21, 21*y = 63 so y = 3.
-18
y=3 y^3(y^3-y)= 3^3(3^3-3)= 27(27-3)= 27(24)=648
Rearrange the equations in the form of:- 6x-6y = 17-11 -4x+6y = 21 6x-6y = 6 -4x+6y = 21 Add both equatios together in order to eliminate y: 2x = 27 Divide both sides by 2: x = 13.5 Substitute the value of x into the equations to find the value of y: x = 13.5 and y = 12.5
y = kx k = y/x = 21/-5 = - 21/5
x-y = 7 so x = 7+y 3x+y = 9 so 3(7+y)+y = 9 21+3y+y = 9 4y = 9-21 4y = -12 y = -3 Substitute the value of y into the original equations to find the value of x: Therefore: x= 4 and y = -3
12