If you mean: (2x-7y)(x+y) then it is 2x squared -5xy -7y squared
x - 7y = 18 ... (A) 2x - 7y = 22 ... (B) Equation (B) - equation (A) gives x = 4 Substituting this value of x in equation (A) gives 4 - 7y = 18 or 7y = -14 which gives y = -2 Solution: (x, y) = (4, -2)
10x-7y = -6 5x+7y = 81 Add both equations to eliminate y: 15x = 75 Divide both sides by 15 to find the value of x: x = 5 Substitute the value of x into the original equations to find the value of y: Therefore: x = 5 and y = 8
(9,6)
4 = 25 - 7y if you need the value of y, transpose -7y to the left side (it will become 7y). transpose 4 to the right side (it will become -4) here it is: 7y = 25-4 7y = 21 divide both sides by 7. y = 3 that's all.
If you mean: (2x-7y)(x+y) then it is 2x squared -5xy -7y squared
This is a difference of two sqaures. 49y2 - z2 = (7y - z)(7y + z)
(4x - 7y)(4x + 7y)
5y+8=7y 2y=8 y=4
(7y + 2)(7y - 2)
If: y = x -2 and 7y -4x = 10 Then: x = 8 and y = 6
x - 7y = 18 ... (A) 2x - 7y = 22 ... (B) Equation (B) - equation (A) gives x = 4 Substituting this value of x in equation (A) gives 4 - 7y = 18 or 7y = -14 which gives y = -2 Solution: (x, y) = (4, -2)
Yx7y = 7y2 (squared )
10x-7y = -6 5x+7y = 81 Add both equations to eliminate y: 15x = 75 Divide both sides by 15 to find the value of x: x = 5 Substitute the value of x into the original equations to find the value of y: Therefore: x = 5 and y = 8
(7,12)
(9,6)
39 - 7y = 18,-7y = 18 - 39-7y = -21-7y/-7 = -21/-7y = 3