To determine the velocity of the runner between 5 seconds and 10 seconds, we need the displacement (change in position) during that time interval. If the runner is moving due north, the velocity will be a vector quantity directed north. Assuming we have the initial and final position data, velocity can be calculated using the formula ( \text{velocity} = \frac{\text{displacement}}{\text{time interval}} ). If the positions are not provided, we cannot compute the exact velocity.
If April swam 50 M North then swam 20 M South back then her velocity would be 16.66. This is a math problem.
The craft's velocity is 232 meters per second north.
The velocity of the train can be calculated by dividing the distance traveled by the time taken. In this case, the train travels 100 miles north in 2 hours, so the velocity is 100 miles / 2 hours = 50 miles per hour. Therefore, the train's velocity is 50 miles per hour to the north.
Yes. Velocity is a vector and therefore requires magnitude and direction: Magnitude: 100 kph Direction: North
Velocity equal distance divided by time. For example, an object that traveled 5 metes in 10 seconds had a velocity of 5/10 meters per second which is .5 meters per second. Velocity is speed in a direction. Sometimes a navigate or positive number is sufficient as the direction. Other times you will need to be more specific, such as .5 meters per second East or 1.3 meters per second 30 degrees East of North.
Positive velocity can be in any direction as long as the object is moving in that direction. For example, a car moving northward has a positive velocity in the north direction.
Velocity = 790.514 m/s North (rounded)The idea is to divide the distance by the time.
He walked 600m in 600 seconds so his velocity is 1m/s (one metre per second)
An object that has both speed and direction is considered to have velocity. Velocity is a vector quantity that includes both the magnitude (speed) and direction of motion of an object. For example, a car moving north at 60 km/h has a velocity of 60 km/h north.
.5 north
The displacement of the car is 200 m (250 m north - 50 m south). The time taken is 15 seconds. Therefore, the velocity of the car is 200 m divided by 15 seconds, which equals 13.33 m/s north.
Distance = Velocity*Time = 25.5*85 metres = 2167.5 metres.
If April swam 50 M North then swam 20 M South back then her velocity would be 16.66. This is a math problem.
a=change over velocity/time 60-initial velocity 45-final velocity 45-60= 15m/s 15/5= 3- acceleration
The rate of change of velocity in a particular direction per unit second is acceleration. Let us assume a body is moving at a speed v' in particular direction, say north, and in t seconds, its velocity increases/decreases to v". So the acceleration is, a=(v"~v')/t
Velocity is speed and its direction. "30 miles per hour" is a speed. "30 miles per hour north" is a velocity". "30 miles per hour north" and "30 miles per hour south" are identical speeds but different velocities.
To find the acceleration of the spaceship, you can use the formula for acceleration, which is the change in velocity divided by the time taken. Here, the change in velocity is 60 m/s (final velocity) - 0 m/s (initial velocity) = 60 m/s. Given that the time taken is 3 seconds, the acceleration is 60 m/s ÷ 3 s = 20 m/s² north.