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How do you find the vertex of 2x2 plus 4 plus 1?
2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)
What is the vertex of the quadratic y -2x2 plus 4x-1?
It is (1, 1).
What is the vertex of -2x2 plus 2x plus 3?
Since this question is in the calculus section, I'm assuming you know how to take the derivative. We know that y = -2x2 + 2x + 3 is a parabola, so it has one vertex, which is a minimum. We can use the first derivative test to find this extreme point.First, take the derivative:y' = -4x + 2Next, set y' equal to zero:0 = -4x + 2Then solve for x:4x = 2x = 2This is the x-coordinate of the vertex. To find the y-coordinate, plug x = 2 back into the original equation:y = -2x2 + 2x + 3y = -8 + 4 + 3y = -1So the vertex is at (2, -1).
What is 8 feet 3inches in inches?
8x12 plus the extra 3 is 99in
Find the vertex of -2x2 plus 2x plus 8?
f(x) = -2x2 + 2x + 8 ∴ f'(x) = -4x + 2 Let f'(x) = 0: 0 = -4x + 2 ∴ 4x = 2 ∴ x = 0.5 Now find the corresponding value: f(0.5) = -2(0.5)2 + 2(0.5) + 8 = -0.5 + 1 + 8 = 8.5 So the vertex of this parabola occurs at the point (0.5, 8.5)
How do you find the vertex of 2x2 plus 4 plus 1?
2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)
What is the vertex of the quadratic y -2x2 plus 4x-1?
It is (1, 1).
What is the vertex of y-2x2-4x-5?
2x2= 4
What is the vertex of -2x2 plus 2x plus 3?
Since this question is in the calculus section, I'm assuming you know how to take the derivative. We know that y = -2x2 + 2x + 3 is a parabola, so it has one vertex, which is a minimum. We can use the first derivative test to find this extreme point.First, take the derivative:y' = -4x + 2Next, set y' equal to zero:0 = -4x + 2Then solve for x:4x = 2x = 2This is the x-coordinate of the vertex. To find the y-coordinate, plug x = 2 back into the original equation:y = -2x2 + 2x + 3y = -8 + 4 + 3y = -1So the vertex is at (2, -1).
Which is the vertex for y equals 2x - 7?
-5
Tell whether the graph opens up or down Find the coordinates of the vertex Write an equation of the axis of symmetry for the equation y equals 2x2 plus 3x plus 6?
y = 2x2 + 3x + 6 Since a > 0 (a = 2, b = 3, c = 6) the graph opens upward. The coordinates of the vertex are (-b/2a, f(-b/2a)) = (- 0.75, 4.875). The equation of the axis of symmetry is x = -0.75.
What is 8 feet 3inches in inches?
8x12 plus the extra 3 is 99in
2x2 - 3x plus 7?
2x2 equals 5
Find the vertex of -2x2 plus 2x plus 8?
f(x) = -2x2 + 2x + 8 ∴ f'(x) = -4x + 2 Let f'(x) = 0: 0 = -4x + 2 ∴ 4x = 2 ∴ x = 0.5 Now find the corresponding value: f(0.5) = -2(0.5)2 + 2(0.5) + 8 = -0.5 + 1 + 8 = 8.5 So the vertex of this parabola occurs at the point (0.5, 8.5)
What is the vertex of x2 plus 18x plus 19?
The vertex is (-9, -62).
What is the vertex of the parabola y-2x2-4x 4?
Assuming the missing symbol there is an equals sign, then we have: y - 2x2 - 4x = 4 We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero: y = 2x2 + 4x + 4 y' = 4x + 4 0 = 4x + 4 x = -1 So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y: y = 2x2 + 4x + 4 y = 2 - 4 + 4 y = 2 So the vertex is at the point (-1, 2)
Vertex for y equals x2 plus 2x plus 1?
The vertex is at (-1,0).
