y=4x-12-3 is the equation of a straight line. It does not have a vertex. Did you mean y=x squared - 12x - 3 ?
The vertex is at the point (0, 4).
y = 3x2+2x-1 Line of symmetry: x = -1/3 Vertex coordinate: (-1/3, -4/3)
y = x2 + 3 Since the x term is missing, the x-coordinate of the vertex is 0. If x = 0, then y = 3. Thus, (0, 3) is the vertex, the minimum point of the parabola.
x squared -2x-3 equals 0 is the same as (x + 1)(x - 3) = 0
y=4x-12-3 is the equation of a straight line. It does not have a vertex. Did you mean y=x squared - 12x - 3 ?
The vertex is at the point (0, 4).
(1/2, 71 and 3/4)or(0.5, 71.75)
y = 3x2+2x-1 Line of symmetry: x = -1/3 Vertex coordinate: (-1/3, -4/3)
y = x2 + 3 Since the x term is missing, the x-coordinate of the vertex is 0. If x = 0, then y = 3. Thus, (0, 3) is the vertex, the minimum point of the parabola.
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
x squared -2x-3 equals 0 is the same as (x + 1)(x - 3) = 0
if x= 3 or -3
The greatness of 4 squared and 3 squared is expressed by the equation: 16 - 9 which equals 7.3 squared equals 3 x 3 = 94 squared equals 4 x 4 = 1616 - 9 = 7
(x, y) = (-3, -3) or (3, 3)
The equation is linear and so has no vertex.
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