voltage = resistance x current
= 5 x 2
= 10 volts
E = I R = (2) (6) = 12 volts
14v
Resistance = 11 ohmsCurrent = 2 amperesVoltage = 22 volts
a(r) = 2pi*r^2 and d = 2r 5 = 2r => r = 5/2 a(r) = 2pi*(5/2)^2 a(r) = 2pi*25/4 a(r) = 25pi/2 or, in decimal form, 39.2699 millimetres2
1) If it is: (r^22)(r^3) = r^(22 + 3) = r^25 (Just add powers) 2) If it is: (r^2)(2)(r^3) = 2[r^(2 + 3)] = 2r^5
To find the voltage required to move 2 amps through a resistance of 5 ohms, you can use Ohm's Law, which states that voltage (V) equals current (I) multiplied by resistance (R). Therefore, V = I × R = 2 amps × 5 ohms = 10 volts. So, a voltage of 10 volts is required.
To calculate the resistance in ohms, you also need to know the voltage. The formula to find the resistance in ohms is R = V^2 / P, where R is the resistance in ohms, V is the voltage, and P is the power in watts.
E = I R = (2) (6) = 12 volts
14v
Can not do it without knowing the voltage I = E/R. Amps = Voltage/Ohms.
I = v/r = 10 / 5 = 2a.
If I0 = V/R, then Inew = (2*V)/(.5*R) = (2 / .5) * (V/R) = 4 *V/R = 4 * I0
ohms=amps/volts Amps= volts/ohms Volts = Amps*Ohms
To calculate the resistance of a 28 watt bulb, you need to know the voltage it operates on. Using the formula P = V^2 / R where P is power (in watts), V is voltage (in volts), and R is resistance (in ohms), you can rearrange the formula to solve for resistance. Without knowing the voltage, the resistance cannot be determined.
Ohms law. R = E/I,where R= resistance in ohms, E = voltage in volts, and I = current in amperes.
The formula you are looking for is Ohm's Law. Voltage = Current x Resistance (v = I x R). To solve for Current the formula is I = V/R.
V=i*r=2*6=12v