voltage = resistance x current
= 5 x 2
= 10 volts
Wiki User
∙ 11y agoE = I R = (2) (6) = 12 volts
14v
Resistance = 11 ohmsCurrent = 2 amperesVoltage = 22 volts
a(r) = 2pi*r^2 and d = 2r 5 = 2r => r = 5/2 a(r) = 2pi*(5/2)^2 a(r) = 2pi*25/4 a(r) = 25pi/2 or, in decimal form, 39.2699 millimetres2
1) If it is: (r^22)(r^3) = r^(22 + 3) = r^25 (Just add powers) 2) If it is: (r^2)(2)(r^3) = 2[r^(2 + 3)] = 2r^5
To calculate the resistance in ohms, you also need to know the voltage. The formula to find the resistance in ohms is R = V^2 / P, where R is the resistance in ohms, V is the voltage, and P is the power in watts.
E = I R = (2) (6) = 12 volts
14v
Can not do it without knowing the voltage I = E/R. Amps = Voltage/Ohms.
If I0 = V/R, then Inew = (2*V)/(.5*R) = (2 / .5) * (V/R) = 4 *V/R = 4 * I0
I = v/r = 10 / 5 = 2a.
ohms=amps/volts Amps= volts/ohms Volts = Amps*Ohms
To calculate the resistance of a 28 watt bulb, you need to know the voltage it operates on. Using the formula P = V^2 / R where P is power (in watts), V is voltage (in volts), and R is resistance (in ohms), you can rearrange the formula to solve for resistance. Without knowing the voltage, the resistance cannot be determined.
The formula you are looking for is Ohm's Law. Voltage = Current x Resistance (v = I x R). To solve for Current the formula is I = V/R.
Ohms law. R = E/I,where R= resistance in ohms, E = voltage in volts, and I = current in amperes.
V=i*r=2*6=12v
V = I times R where V = voltage, I = current and R = resistance. Further, I = V / R.As I = V / R, I = 60 /12 = 5 amps.V=IR , where V=60 volts R=12 ohms so I = V/R = 60/12 = 5 Amp.