voltage = resistance x current
= 5 x 2
= 10 volts
E = I R = (2) (6) = 12 volts
14v
Resistance = 11 ohmsCurrent = 2 amperesVoltage = 22 volts
The formula for calculating resistance in ohms (Ω) is given by Ohm's Law, which states that resistance (R) is equal to voltage (V) divided by current (I). Mathematically, this is expressed as R = V/I, where R is resistance in ohms, V is voltage in volts, and I is current in amperes. This relationship helps to determine how much resistance is present in an electrical circuit.
a(r) = 2pi*r^2 and d = 2r 5 = 2r => r = 5/2 a(r) = 2pi*(5/2)^2 a(r) = 2pi*25/4 a(r) = 25pi/2 or, in decimal form, 39.2699 millimetres2
To find the voltage required to move 2 amps through a resistance of 5 ohms, you can use Ohm's Law, which states that voltage (V) equals current (I) multiplied by resistance (R). Therefore, V = I × R = 2 amps × 5 ohms = 10 volts. So, a voltage of 10 volts is required.
To calculate the resistance in ohms, you also need to know the voltage. The formula to find the resistance in ohms is R = V^2 / P, where R is the resistance in ohms, V is the voltage, and P is the power in watts.
E = I R = (2) (6) = 12 volts
14v
Can not do it without knowing the voltage I = E/R. Amps = Voltage/Ohms.
I = v/r = 10 / 5 = 2a.
If I0 = V/R, then Inew = (2*V)/(.5*R) = (2 / .5) * (V/R) = 4 *V/R = 4 * I0
ohms=amps/volts Amps= volts/ohms Volts = Amps*Ohms
That depends on what voltage it's designed to operate from. Power = (voltage)2 / R R = Voltage2 / power If it's a 117-volt bulb, R = (117)2 / 28 = 489 ohms. If it's a 240-volt bulb, R = (240)2 / 28 = 2,057 ohms.
Ohms law. R = E/I,where R= resistance in ohms, E = voltage in volts, and I = current in amperes.
The formula you are looking for is Ohm's Law. Voltage = Current x Resistance (v = I x R). To solve for Current the formula is I = V/R.
V=i*r=2*6=12v