Resistance = 11 ohms
Current = 2 amperes
Voltage = 22 volts
14v
E = I R = (2) (6) = 12 volts
voltage = resistance x current = 5 x 2 = 10 volts
(2, 11)
X=5Y= 92x + 11= ?2(5)+11=?10+11= 21
14v
E = I R = (2) (6) = 12 volts
2 volts across 100 kOhms produces 0.02 milliamps (or 20 microamps) of current. Ohm's law: Voltage = Amperes * Ohms, so Amperes = Voltage / Ohms.
Ohms Law! E=IR Voltage equals current times resistance. Get out the old calculator...
Current equals Voltage divided by Resistance. 9/2=4.5 amps.
The power (P) can be calculated using the formula P = V^2 / R, where V is the voltage (23V) and R is the resistance (470 ohms). Plug these values into the formula to find the power in watts.
voltage = resistance x current = 5 x 2 = 10 volts
Very basically, simply divide the voltage by the amperage. Thsi is not for calculating Ohms of resistance, just Ohms. For example, a 9 volt battery that delivers 3 amps has 3 ohms. To calculate ohms of resistance we use the ohms law. This measures the difference in current flow in amps (amps/current is amount or volume of flow, volts is power pushing that current, sort of) and voltage. For instance, measure the amps and voltage at the source and record the ohms. Then record the same at the end point the difference in ohms is ohms of resistance. So, if we measure 10 volts and 2 amps at the source we have 5 ohms. at the end point we have 8 volts and 1 amp we have 8 ohms. therefore we have 13 ohms of resistance. 1 Determine current. Current is the flow of electricity measured in amps. For example a current has four amps in the circuit. 2 Determine voltage. Voltage is the difference in electrical potential from two points, measured in volts. For example, there is two-hundred volts in a circuit. 3 Divide voltage by current to calculate resistance. Resistance is measured in ohms. In the example, two-hundred volts divided by four amps equals fifty ohms. 4 To get ohms of resistance, measure the end point. at the endpoint we have 100 volts and 2 amps=50 ohms. therefore we have 100 ohms of resistance
12 voltage
The resistors each have a value of 20 ohms. The way to discover it is to apply Ohm's law. It (Ohm's law) comes in 3 "flavors" that look a bit different but all say exactly the same thing. Here they are: E = I x R [Voltage equals current times resistance.] I = E/R [Current equals voltage divided by resistance.] R = E/I [Resistance equals voltage divided by current.] In these equations, voltage is E, current is I and resistance is R. They are measured in units of volts, amperes (or amps) and ohms, respectively. Your problem gives us an applied voltage of 8 volts and a current flow of 0.2 amps. The formula that probably works best is R = E/I for this one because you have volts and amps. In this case, R = 8/0.2 = 40 ohms. But that's the total resistance in the circuit, and you said that a pair of equal resistors are connected, so the pair of resistors has a total resistance of 40 ohms. The rule for finding total resistance for resistors in series is that we add them up. R1 + R2 = 40 ohms. And since R1 = R2 here, 2 x R1 or 2 = 40 ohms, and R1 or 2 = 20 ohms. Either resistor has a resistance of 20 ohms, and that means they both do. Easy as pie.
Current, by Ohm's Law, is voltage divided by resistance, so, 18 volts divided by 2 ohms is 9 amperes.
Ohm's Law: voltage is current times resistance, so 8 amps times 2 ohms is 16 volts.