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25m x 6m x 18m = 2,700 cubic m

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Q: What is the volume of 25m x 6m x 18m?
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What is the volume of a tunnel with radius of 6meters and length of 25meters and height of 7meters?

I presume the tunnel has an arch shaped cross-section with a semicircle on top of a rectangle. In this case the volume of the tunnel is the volume of the cuboid bottom plus the volume of half cylinder which forms the top. The volume of the half cylindrical top is ½πr²h = ½ × π × (6m)² × 25m = 450π m³ The volume of the cuboid is length × width × height. The length is 25m. The width is the diameter of the top half cylinder which is twice the radius at 2 x 6m = 12 m. The height is not clear. I am going to presume it is to the top of the arch, so that the height of the cuboid is the height less the radius of the cylinder, namely 7m - 6m = 1m. Thus the volume of the cuboid bit is 25m x 12m x 1m = 300 m³ Thus the volume of the tunnel as a whole is 300 m³ + 450π m³ ≈ 1713.72 m³ (If the 7m height refers to the height of the vertical walls, then the volume of the cuboid is 25m x 12m x 7m = 2100 m³ and the volume of the tunnel is 2100 m³ + 450π m³ ≈ 3513.72 m³.)


What is the volume of a right pyramid whose base is a square with a side of 6 m long and whose altitude is equal to the base side?

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What is the volume of water in a rectangular swimming pool that is 18m long and 10m wide and has an average depth of 2.5m. give your answer in cubic meters?

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