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25m x 6m x 18m = 2,700 cubic m
how to find the dept of the pool if it is 15m long and 6m wide
Volume = 753.98224m3
V = 169.65 m3
A cylinder with a radius of 1.25 meters and a height of 6 meters has a volume of 29.45 cubic meters.
Volume= 2.4m * 6m * 8m= 115.20 cubic meters
To make a 0.25M solution of ammonium sulfate at a concentration of 6M, you would need to dilute the 6M solution. Assuming you have 1 liter of the 6M solution, you can calculate the volume needed for dilution using the formula: (C1V1 = C2V2), where C1 = 6M, V1 = volume of the 6M solution (in liters), C2 = 0.25M, and V2 = total volume of the diluted solution (in liters). Once you have the volume, you can convert it to grams using the molar mass of ammonium sulfate.
25m x 6m x 18m = 2,700 cubic m
how to find the dept of the pool if it is 15m long and 6m wide
Volume = 753.98224m3
Volume pyramid = 1/3 x base_area x height = 1/3 x (6m x 6m) x 6m = 72m3.
1m times 5m times 6m
If it is a rectangular tank, the volume is length times width times height, 6m x 6m x 3m, or 108m3.
V = 169.65 m3
6m-6m = 0
To calculate the volume of air that can enclose the tent, you would use the formula for the volume of a rectangular prism, which is length x width x height. In this case, the length is 6m, the width is 6m, and the height is 4m. Therefore, the volume of air that can enclose the tent would be 6m x 4m x 4m = 96 cubic meters.
You would need to dilute the 6M acetic acid solution by adding the appropriate volume of water. To prepare 500 mL of 1M solution, you would need to take (1/6)th of the volume of the 6M solution, which is (1/6) x 500 mL = 83.33 mL of the 6M solution. Dilute this with water to reach a final volume of 500 mL.