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A piece of granite has a volume of 340 cm and a mass of 918 g Find the density?
The density of a piece of granite with a volume of 340 cm and mass of 918 g would be 1,400 grams. This is a math problem.
What is the volume of a piece of metal if the density is 2.3glml and the mass is 1.5g?
Density = Mass/Volume so Volume = Mass/Density. That is, Vol = 1.5 g/2.3 g/ml = 0.652 ml approx.
What is the density of a piece of quartz that has a mass of 13 g and a volume of 5 cm3?
13/5 = 2.6 g per cm3
What is the density of a 49.8g piece of pumice that has a volume of 83cm3?
density = mass/volume 49.8/83 =0.6 g per cm3
A nugget of gold with a mass of 521 g is added to 50.0 mL of water The water level rises to a volume of 77.0 mL What is the density of the gold?
Assuming the gold nugget is solid and pure (unlikely in real life!) The volume of the nugget is 77.0 - 50.0 mL = 27.0 mL So density = mass/volume = 521/27.0 = 19.3 g per mL.
What is the volume of a 2 g piece of gold?
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What is the volume of 2 g a piece of gold?
To calculate the volume of a piece of gold, you need to know its density. Gold has a density of around 19.32 g/cm^3. Using this density value, you can calculate the volume by dividing the mass (2 g) by the density. The volume of 2 g of gold would be approximately 0.104 cm^3.
a piece of gold has a mass of 9.66 g. what is its volume?
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What is the volume occupied by 450 g of gold if the density of gold is 19. g per cm3?
The volume of gold can be calculated by dividing the mass by the density. In this case, 450 g divided by 19 g/cm^3 gives a volume of 23.68 cm^3. Therefore, 450 g of gold occupies a volume of 23.68 cm^3.
What is the volume of a piece of magnesium that weighs 2.70 g?
The volume is 1.55 cm^3.
If pure gold has a density of 19.32 gcm3. How large would of gold be if it had a mass of 318.97 g?
The volume of the gold can be calculated using the formula: Volume = Mass / Density. Substituting the given values, Volume = 318.97 g / 19.32 g/cm^3 = 16.52 cm^3. So, the gold would have a volume of 16.52 cm^3.
If the mass density of gold is 193gramscubic centimeter and you were gave 15 kilograms of gold what is the volume?
To find the volume of gold, first convert the mass of gold to grams (1 kg = 1000 g), so 15 kg = 15000 g. Then, use the mass density formula: density = mass/volume, rearrange it to find volume: volume = mass/density. Plug in the values: volume = 15000 g / 19.3 g/cm^3 = 777.2 cubic centimeters.
Is the volume of gold 20g greater than the volume of lead 10g?
We need to calculate the volume of a metal from the density to be sure. Density of pure gold = 19.3  g·cm-3Density of pure lead = 11.34  g·cm-3The volume of 20 g of gold = mass/density = 20 [g] / 19.3  g·cm-3 = 1.036 cm3 The volume of 10 g of lead = mass/density = 10 [g] / 11.34  g·cm-3 = 0.882 cm3 Hence, the volume of 20 g of gold is slightly greater than that of 10 g of lead. =========================
The density of gold is 19.3 g cm3 The density of iron pyrite is 5.0 g cm3 If a nugget of iron pyrite and a nugget of gold each have a mass of 50 g what can you conclude about the volume of each nugget?
The nugget of gold has a volume of 2.6 cm3, and the nugget of pyrite has a volume of 10 cm3.
Find the density of a piece of paper that has a mass of 15.5 g and a volume of 27.0 cm3?
The density of the piece of paper is calculated by dividing its mass (15.5 g) by its volume (27.0 cm3). Density = mass/volume = 15.5 g / 27.0 cm3 = 0.574 g/cm3.
How much volume will 180.0 g of gold occupy?
The volume of a substance can be calculated using its density. The density of gold is approximately 19.3 g/cm³. Using the formula: Volume = Mass / Density Volume = 180 g / 19.3 g/cm³ Volume ≈ 9.33 cm³ Therefore, 180.0 g of gold will occupy approximately 9.33 cm³.
A 34.5-g gold is dropped into a graduated cylinder containing water by how many milliliters does the measured volume increase?
The volume increase will be equal to the volume of the gold submerged in the water. The volume of the gold can be calculated by dividing its mass by its density (19.32 g/cm³ for gold). Submerging the gold in water will displace an equal volume of water, resulting in the measured volume increase.
