The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height
Trying to figure this out too...
If the area of the base of the tetrahedron is A square units and the vertical height is h units, then the volume is V = 1/3*A*h cubic units. If the tetrahedron is regular, with sides of length of length s units, then V = sqrt(2)/12*s3 cubic units.
formula for finding the volume of tetrahedrone is=sqrt(2)*side*3/4 if side is 3 then the volume is 9(sqrt(2))/4
given the length of a side as S, the volume is: SQRT(2)*S3/12 Where SQRT(2) is the square root of 2 (~1,414) and S3 is the length of a side cubed.
The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height
942.80904 cm3
Trying to figure this out too...
If the area of the base of the tetrahedron is A square units and the vertical height is h units, then the volume is V = 1/3*A*h cubic units. If the tetrahedron is regular, with sides of length of length s units, then V = sqrt(2)/12*s3 cubic units.
Assuming you mean a tetrahedron, the volume is 1/3*area of base*height cubic units.
I am not a tetrahedron!
formula for finding the volume of tetrahedrone is=sqrt(2)*side*3/4 if side is 3 then the volume is 9(sqrt(2))/4
given the length of a side as S, the volume is: SQRT(2)*S3/12 Where SQRT(2) is the square root of 2 (~1,414) and S3 is the length of a side cubed.
A tetrahedron has 4 faces.
Well, a tetrahedron has four sides. A regular tetrahedron is a triangular pyramid.
A tetrahedron must be plane faced and so, it is just an ordinary tetrahedron.
He faced a tetrahedron question in the exam paper. This is a sample sentence using the word tetrahedron.