V = 1/3 * base area * height.
The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height
The volume of a tetrahedron is one-sixth of the volume of a parallelepiped because a tetrahedron can be thought of as a pyramid with a triangular base. When a tetrahedron is inscribed within a parallelepiped, it occupies one-sixth of the space defined by the parallelepiped's volume. Since a parallelepiped can be divided into six such tetrahedra, this means the volume of the tetrahedron is 1/6 of the parallelepiped. However, if the parallelepiped is defined by its full height and includes the whole base area, the tetrahedron's volume is one-sixteenth of the total volume when considering the full dimensions of the parallelepiped.
Trying to figure this out too...
If the area of the base of the tetrahedron is A square units and the vertical height is h units, then the volume is V = 1/3*A*h cubic units. If the tetrahedron is regular, with sides of length of length s units, then V = sqrt(2)/12*s3 cubic units.
formula for finding the volume of tetrahedrone is=sqrt(2)*side*3/4 if side is 3 then the volume is 9(sqrt(2))/4
The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height
The volume of a tetrahedron is one-sixth of the volume of a parallelepiped because a tetrahedron can be thought of as a pyramid with a triangular base. When a tetrahedron is inscribed within a parallelepiped, it occupies one-sixth of the space defined by the parallelepiped's volume. Since a parallelepiped can be divided into six such tetrahedra, this means the volume of the tetrahedron is 1/6 of the parallelepiped. However, if the parallelepiped is defined by its full height and includes the whole base area, the tetrahedron's volume is one-sixteenth of the total volume when considering the full dimensions of the parallelepiped.
942.80904 cm3
Trying to figure this out too...
If the area of the base of the tetrahedron is A square units and the vertical height is h units, then the volume is V = 1/3*A*h cubic units. If the tetrahedron is regular, with sides of length of length s units, then V = sqrt(2)/12*s3 cubic units.
Assuming you mean a tetrahedron, the volume is 1/3*area of base*height cubic units.
I am not a tetrahedron!
formula for finding the volume of tetrahedrone is=sqrt(2)*side*3/4 if side is 3 then the volume is 9(sqrt(2))/4
The least number of planes that can enclose a solid is four, which form a tetrahedron. A tetrahedron is a three-dimensional shape with four triangular faces, four vertices, and six edges. Each face of the tetrahedron is a triangle, and together they completely enclose a volume in space.
given the length of a side as S, the volume is: SQRT(2)*S3/12 Where SQRT(2) is the square root of 2 (~1,414) and S3 is the length of a side cubed.
A tetrahedron has 4 faces.
Well, a tetrahedron has four sides. A regular tetrahedron is a triangular pyramid.