200ml of solution x 20% of alcohol = 40ml of alcohol..
Answer:170mL of 5% acid solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solutionLet x = 5% acid solutiony = 25% acid solution Equations:x + y = 200mL ----equation (1)0.05x + 0.25y = 0.08 * 2000.05x + 0.25y = 16multiplying by 1005x + 25y = 1600 ----equation (2)eliminating equations (1) and (2)-5(x + y = 200)-5-5x -5y = -10005x +25y = 1600=========20y = 600y=30substitute x=30 to equation (1)x + 30 = 200x = 200 - 30x = 170thus 170mL of 5% solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solution
66.67
That is 7.055 ounces.
You can fill 15 bottles of 200ml with a 3L jug of cordial.
No, it is not.
To prepare 200ml of 80% glycerol solution, you would mix 160ml of glycerol (200ml x 80%) with 40ml of water. Calculations: 200ml x 80% = 160ml glycerol, and 200ml - 160ml = 40ml water needed. Mix the glycerol and water thoroughly to obtain the 80% glycerol solution.
11 mL is the smallest volume of the three.
To prepare 200ml of 0.1 N ethyl acetate solution, you will need to calculate the amount of ethyl acetate needed. Since the molecular weight of ethyl acetate is around 88.11 g/mol, for 200ml of 0.1 N solution, you would need around 1.76g of ethyl acetate. Dissolve this amount of ethyl acetate in distilled water to make up the final volume to 200ml.
20ml
The initial amount of KCl in the solution is 12mL (12% of 100mL). When 200mL of water is added, the total volume becomes 300mL. You would then divide the initial amount of KCl (12mL) by the total volume (300mL) and multiply by 100 to get the final concentration of KCl in the solution.
To prepare a 200ml solution with a sodium concentration of 5ppm from a 1000ppm stock solution, you will first dilute the stock solution by a factor of 200. So, take 0.2ml of the 1000ppm solution and dilute it to 40ml with water. This will give you a solution with a concentration of 50ppm. Then, take 0.4ml of this 50ppm solution and dilute it to a final volume of 200ml with water to achieve the desired 5ppm sodium concentration.
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
d=m/v so 200g/200ml= 1g/ml
Answer:170mL of 5% acid solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solutionLet x = 5% acid solutiony = 25% acid solution Equations:x + y = 200mL ----equation (1)0.05x + 0.25y = 0.08 * 2000.05x + 0.25y = 16multiplying by 1005x + 25y = 1600 ----equation (2)eliminating equations (1) and (2)-5(x + y = 200)-5-5x -5y = -10005x +25y = 1600=========20y = 600y=30substitute x=30 to equation (1)x + 30 = 200x = 200 - 30x = 170thus 170mL of 5% solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solution
2.5
The volume of 200 ml is 200 millilitres. 200 milligrams is irrelevant to the question.
a lot