A pentahedron. One example is a quadrilateral based pyramid.
the pyramid is a solid triangle. aka pyramid. A cube is well a solid square that is 3D. So is a pyramid.
The volume for any pyramid = 1/3*base area*perpendicular height
The solid commonly called a dodecahedron is not a solid pyramid but the name simply means a solid shape with 12 faces and so, a pyramid on a 11-sided polygonal base will be a dodecahedron.
for example, a trapeziodal pyramid of ABCDEFGJ. With a height H . Volume is area of the base EFGJ which is half (a + b)h where h is the length between the two parallel lines. Therefore the volume is the area of the base times the heigth H
The number of vertices on a solid pyramid will depend on its base as for example if it is a triangular based pyramid (tetrahedron) then it will have 4 vertices, 6 edges and 4 faces.
The volume of the similar solid would be 16M squared.
They are solid shapes as for example a pyramid
A pentahedron. One example is a quadrilateral based pyramid.
There kind of solid object will determine the formula that will be used to find its volume.
the pyramid is a solid triangle. aka pyramid. A cube is well a solid square that is 3D. So is a pyramid.
The volume of the pyramid is: 48 cm3
You place it in water to see the volume of water it displaces. Fill a large, graduated measuring cylinder to about halfway with water (say to 50mL) Put the irregular solid in, and measure the volume it reads (solid + water). (say it reads 80mL) So the volume of the irregular solid will be: volume(solid+water) - volume(water). For example, the volume of the water was 50mL, and when the solid was added, the volume increased to 80mL. The volume of the solid would be 80mL - 50mL. So it would be 30mL.
A pyramid is a solid figure with one vertix.
A pyramid has the solid quadrilateral pyramid solid shape.However there are also pyramids with geometrical polyhedra/platonic solid shapes of tetrahedron.
You can find some of these solutions online. An example would be the volume of frustum or a similar problem.
The volume for any pyramid = 1/3*base area*perpendicular height