We would need to know what wavefunction to respond to this question.
One of many, many possibilities would simply be y = sin x.
If ( y = x ), then to express ( x ) in terms of ( y ), you can simply rearrange the equation. This gives you ( x = y ). Thus, ( x ) is equal to ( y ).
No. It represents a function of x in terms of y but, in strict mathematical terms, not a function of y in terms of x. This is because the mapping from the domain (x values) to the range (y values) is 1-to-many. For each value of x, there can be 2 values of y. For example, x = 0 gives y2 = 1 so that y = ±1.
In mathematical terms, a number x is less than y if y - x is positive.
9
Put x = 0 in the equation for y in terms of x.
If ( y = x ), then to express ( x ) in terms of ( y ), you can simply rearrange the equation. This gives you ( x = y ). Thus, ( x ) is equal to ( y ).
A wavefunction is a representation of the state of a quantum system. A quantum state is a vector belonging in an abstract space (the Hilbert space), while a wavefunction is a complex function given in terms of a Hermitian variable (usually position or momentum). When "wavefunction" is used unqualified (as opposed to "wavefunction in momentum space"), it is taken to mean the wavefunction in terms of position. In case of single-particle systems, the modulus squared of the wavefunction at a given position represents the probability density of the particle to be at that position.
The function of y in terms of x represents how the value of y changes based on the value of x in a mathematical equation or relationship.
No. It represents a function of x in terms of y but, in strict mathematical terms, not a function of y in terms of x. This is because the mapping from the domain (x values) to the range (y values) is 1-to-many. For each value of x, there can be 2 values of y. For example, x = 0 gives y2 = 1 so that y = ±1.
In mathematical terms, a number x is less than y if y - x is positive.
9
Put x = 0 in the equation for y in terms of x.
x + 5y = 0 so x = -5y or y = -x/5 You can express x in terms of y or y in terms of x but it is not possible to solve a single linear equation in two variables.
x+y+x =2x +y... I got this by simply combining like terms. I added the x's( 2x) and kept the y there which gave the answer
x= z2 - 3
To solve for y in terms of x, divide both sides of the equation by 2: y = x/2.If x=2y then you have already solved for x.
2sin(y) = 2x/sqrt(1+x^2)