Wiki User
∙ 13y ago4.9695 nm
Wiki User
∙ 13y agoBecause the wavelength is not 1050 metres but 1050 nanometres.
I assume you mean 4 X 10^-17 Joules.Energy = Planck's constant * speed of light/wavelength in meters4 X 10^-17 Joules = (6.626 X 10^-34 J*s)(2.998 X 10^8 m/s)/wavelengthwavelength in meters = (6.626 X 10^-34)(2.998 X 10^8)/(4 X 10^-17)= 4.9662 X 10^-9 metersor4.97 nanometers
2.48 X 10^-17 J
Wavelength = (speed) divided by (frequency) = 10/0.5 = 20
Wavelength = speed/frequency = 30/10 = 3 meters
To find the wavelength of the photon, you can use the formula: wavelength = (Planck's constant) / (photon energy). Substituting the values, the wavelength is approximately 1.024 x 10^-7 meters.
The wavelength of a photon can be calculated using the equation: wavelength = Planck's constant / photon energy. Given the photon energy, you can plug in the values to find the corresponding wavelength.
The wavelength of a photon can be calculated using the equation E = hc/λ, where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength. From this equation, you can rearrange it to solve for the wavelength, which would be approximately 6.10 x 10^-7 meters for a photon with an energy of 3.26 x 10^-19 J.
The frequency of a photon with a wavelength of 488.3 nm is approximately 6.15 x 10^14 Hz. The energy of this photon is approximately 2.54 eV.
The energy of a photon is given by E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. Plugging in the values, the energy of a photon with a 9 x 10^-8 m wavelength is approximately 2.21 x 10^-18 Joules.
610 nm
The energy of a photon is given by E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. Plugging in the values, the energy of an ultraviolet photon with a wavelength of 1.18 nm is approximately 10.53 eV.
The wavelength of a photon can be calculated using the equation E = hf, where E is the energy of the photon, h is Planck's constant (6.63 x 10^-34 J s), and f is the frequency of the photon. From this, you can calculate the frequency of the photon using f = E/h. Then, you can use the speed of light equation c = fλ to find the wavelength with λ = c/f. Substituting the values accordingly, you can find the wavelength of the photon with 3.38 x 10^-19 J of energy.
The energy of a photon can be calculated using the formula E=hf, where E is energy, h is Planck's constant (6.63 x 10^-34 J.s), and f is the frequency of the photon. Alternatively, you can use the formula E=hc/λ, where c is the speed of light (3.00 x 10^8 m/s) and λ is the wavelength of the photon.
2.21•10^-18 J
The energy of the electron decreased as it moved to a lower energy state, emitting a photon with a wavelength of 550 nm. This decrease in energy corresponds to the difference in energy levels between the initial and final states of the electron transition. The energy of the photon is inversely proportional to its wavelength, so a longer wavelength photon corresponds to lower energy.
440 - 460 nm