Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
Area = Length*Width so Width = Area/Length = 255/17 ft = 15 feet.
The perimeter of a standard- sized rectangular rug is 94 ft. the length is 3 ft more than the width. Find the length and the width.
The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
1 acre = 43560 sq ft→ 0.18 acre = 0.18 x 43560 sq ft= 7840.8 sq ft.There is no definite answer for the length and width of a building lot as the building lot can have any length and width as long asits area(length x width) is 7840.8 sq ft.If it is a square building lot, it would be approx 88.55 ft by 88.55 ft.However, if it is rectangular, it could be approx 98 ft by 80 ft, or 131 ft by 60 ft, or 196 ft by 40 ft, or 157 ft by 50 ft, or even 7480 ft by 1 ft!
Area = Length*Width so Width = Area/Length = 255/17 ft = 15 feet.
Runway: 25R Length x Width: 12923 ft x 150 ft Runway: 07L Length x Width: 12923 ft x 150 ft Runway: 25L Length x Width: 11095 ft x 200 ft Runway: 24R Length x Width: 8926 ft x 150 ft Runway: 24L Length x Width: 10885 ft x 150 ft Runway: 07R Length x Width: 11095 ft x 200 ft Runway: 06R Length x Width: 10885 ft x 150 ft Runway: 06L Los Angeles Ramp/Taxi: 131.45
The perimeter of a standard- sized rectangular rug is 94 ft. the length is 3 ft more than the width. Find the length and the width.
From here, it appears that the length is double the width.
Easy. Width = 2ft, Length = 4 ft, therefore the Area = 8 ft.
The area formula is: Area = length x width Let: length = 40 ft width = 50 ft Then: A = 40 ft x 50 ft = 2000 ft²
The number of possibilities is endless. Although some may be absurd, you could have pools whose length and width are: 13300 ft and 1 ft 10000 ft and 1.33 ft 1330 ft and 10 ft 1000 ft and 13.3 ft etc. Then you could have 6650 ft and 2 ft 665 ft and 20 ft