p=2l+2w
34= 2(10) +2w
34= 20 +2w
14= 2w
w=7
I assume you are referring to a rectangle. Just add the lengths of all four sides.
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
40cm2
The diagonal is 26cm
what is the perimeter of a 11cm x 10cm rectangle answer 42
Width = 10cm.. i think Length = 68cm
Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm
I assume you are referring to a rectangle. Just add the lengths of all four sides.
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
40cm2
The diagonal is 26cm
what is the perimeter of a 11cm x 10cm rectangle answer 42
The perimeter of a rectangle is equal to 2 x length + 2 x width. (2 x 24 cm) + (2 x 10 cm) = 48 cm + 20 cm = 68 cm
infinitely far
In order to find the area of a rectangle, multiply the length by the width of the rectangle. For example: If the length of a rectangle is 5cm and the width of a rectangle is 2cm, then the area of the rectangle would be 5cm X 2cm = 10cm².
10 × 5 = 50Therefore, the width is 5 centimetres.