Q: What is the width of a rectangle that has an area of 48 feet and length of 2 feet?

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The area of a rectangle is length x width.

The area of the rectangle is 72 square feet

area = length x width width = area/length 16/8 = 2 feet

Area of a rectangle = length * width = 72 feet-squared

Area = Length * Width So Length = Area / Width Length = 132/1q = 132/q feet

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The area of a rectangle is length x width.

The area of the rectangle is 72 square feet

Area of a rectangle is length times width, therefore if the length is two feet longer than the width then the length is 9 and the width is 7, when they are multiplied you get 63

Area of a rectangle: length times width Width=11 Length= 11x3= 33 11x33= 363 square feet

The length is 7 feet and the width is 5 feet

The width is 6 feet. The length is 8 feet.

area = length x width width = area/length 16/8 = 2 feet

The area of rectangle is : 120.0

Area of a rectangle = length * width = 72 feet-squared

Area = Length * Width So Length = Area / Width Length = 132/1q = 132/q feet

The width is 16 feet

width=16 and length=20